Question

1. Untuk suatu nilai x > fungsi In(x) dapat diaproksimasi dengan menggunakan deret sbb.: X-1 1 In(x) = 1 + 3 Buatlah algoritma/program dengan menggunakan call function untuk mengaproksimasi fungsi In(x) tersebut untuk suatu nilai x sampai dengan N suku pertama. Hint sebagai input adalah nilai x dan N.

For an x > 1/2, function ln(x) can be approximately using the series

questions:

Create an algorithm or program using the "call function" to approximate the function ln(x) for an x to the N first term.

Hint: as an input is an x and N

Answer 1

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Solution is in C programming.

main.c saving... 1 #include <stdio.h> 2 #include<math.h> int main(void) 3 4 { 5 6 7 8 long double x; int N; printf("Enter value of x: "); scanf("%Lf",&x); printf("Enter value of N: "); scanf("%d",&N); if(x<=1/2) 9 10 11 12 13 14 15 16 17 { } printf("x must be greater than 1/2\n"); else { long double Inx=0; for(int i=1;i<=N;i+=1) 18 Inx+=((long double)(1/(float)(i)))*pow((x-1)/x,i); سها 19 20 21 22 23 24 printf("\n(%Lf)=%LF\n",x,lnx); } return 0; 25 بہا

#include <stdio.h> #include<math.h> int main(void) { long double x; int N; printf("Enter value of x: "); scanf("%Lf",&x); printf("Enter value of N: "); scanf("%d",&N); if(x<=1/2) { printf("x must be greater than 1/2\n"); } else { long double lnx=0; for(int i=1;i<=N;i+=1) { lnx+=((long double)(1/(float)(i)))*pow((x-1)/x,i); } printf("ln(%Lf)=%Lf\n",x,lnx); } return 0; }

?./main Enter value of x: 3 Enter value of N: 100 ln(3.000000)=1.098612

Solution using calculator

In(3) = 1.09861228867 Rad Deg x! ) % AC Inv sin In 7 8 9 1. TT cos log 4 5 6 X e tan ✓ 1 3 - N Ans EXP x 0 IL +