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To test Ho: σ=4.6 versus H1: σ≠4.6​, a random sample of size n=11 is obtained from...

To test Ho: σ=4.6 versus H1: σ≠4.6​, a random sample of size n=11 is obtained from a population that is known to be normally distributed.

​(a) If the sample standard deviation is determined to be s=5.6​,

compute the test statistic.

(b) If the researcher decides to test this hypothesis at the α=0.01 level of​ significance, use technology to determine the​ P-value.

​(c) Will the researcher reject the null​ hypothesis?

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Answer #1

(a) The test-statistic for the given hypothesis for population standard deviation(a is as-

(n 1)s2 -2 2, and degrees of freedom, df n-1.

Given:

sample standard deviation, s 5.6

sample size, n 11

g 4.6

(n 1)s (11 1)5.62 14.82041588 2 4.62

So, the test-statistics is computed as 14.82041588

(b) The level of significance is given as = 0.0 , so we need to find the p-value for the calculated test-statistic and then we have to compare it with the significance level \alpha to make decision.

14.82041588, df n- 1- 11 1 10

2P2 14.82041588, df 10) 2(0.1387476) 0.2774953 p -value _

So, the p-value is calculated as p value 0.2774953

(c) 0.01, p-value 0.2774953

Since, \mathrm{p-value>\alpha}\Rightarrow \mathbf{We\:fail\:to\:reject\:null\:hypothesis\:H_{0}}

So, at = 0.0 the sample does not provide enough evidence to support the alternative hypothesis, hence we fail to reject the null hypothesis, \mathrm{H_{0}:\sigma=4.6}

> But how did you obtain the p-value?

May Arauz G Thu, Nov 25, 2021 10:07 AM

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