Solution:
Mass of the ball = 2 grams
Length = 1 m
angle = = 16 deg
From the given figure, we can first find the distance between the two charges.
The Tension in the string is along the string , and directed up towards the fixed point along the string.
It has X and Y components directed along the horizontal towards the left and vertical, upwards respectively.
Cos16 = Ty/T; Sin16 = Tx/T
Since the charges are equal, they experience force of repulsion given by tghe Coulomb's law:Fe=kq2/d2
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