Question

Using SEMF calculate the total binding energy B and the value of B/A for $_{4}^{8}\textrm{Be}$ , $_{6}^{12}\textrm{C}$ , $_{26}^{56}\textrm{Fe}$ and $_{82}^{208}\textrm{Pb}$ . b) Based on your result is $_{4}^{8}\textrm{Be}$ stable against alpha radioactivity? c) More precise values of binding energies for $_{4}^{8}\textrm{Be}$ and He/alpha particle are 56.5 MeV and 28.29 MeV, respectively. Write down the reaction of the $_{4}^{8}\textrm{Be}$ alpha decay and calculate the energy released in it.

Answer 1

According to semi empirical energy formula where, a_v = 15.75Mev a_s = 17.800 a_c = 0.71 a_n = 2.27 delta = 34 a = 8,z = 4 B..E = 59.04 Mev a = 56,z = 26 B.E = -91.68 Mev a = 56,z = 26 B.E = 496.02 Mev a = 208,z = 82 B.E = 626.71 Mev in this case, binding energy per nucleon is minimum for we now, least the energy per nucleon more the unstability fission process so is most stable among these four against alpha radio activity so, energy released in the reaction Q = 56.5-2 times 28.29 = -0.08Mev in other words, 0.08Mev is absorbed or required to make the reaction happened