(1) when 2a charge particle move perpendicular in magnetic field than it trajectory will be a circle.
(2) according to lentz law induced magnetic field in conductor
Oppose change in magnetic flux through the conductor
(3) total charge is equal to area of I-t curve
Charge (Q) = 2x3 + 1.5x5 = 14C
(4) total energy (E) = I2Rt
E, = 3(18.75 + 11.25)
E = 90 Joule
please answer all questions Item 2 Part A When a charged particle moves perpendicularly to a...
Lenz's law states that an induced magnetic field in a conductor Opposes the change in flux through the conductor. Opposes the applied magnetic field. Induces a matching electric field that causes a current. Opposes the applied flux through the conductor.
Part A. Considering light at the two ends of the visible light spectrum, violet light has a _____ wavelength and a _____ photon energy than red light. A.Shorter, higher B.Longer, higher C. Longer, lower D. Shorter, lower Part B. Lenz’s law states that an induced magnetic field in a conductor A. Opposes the change in flux through the conductor. B. Opposes the applied magnetic field. C. Induces a matching electric field...
Hello, these two screen shots are one entire problem not two separate ones so PLEASE answer ALL of the parts to the question! THANKS Problem Set 11 Begin Date: 11/12/2019 12:01:00 AM -- Due Date: 11/22/2019 5:00:00 PM End Date: 11/24/2019 11:59:00 PM (25%) Problem 3: Considering the three situations below: *7% Part (a) This hexagonal loop of wire is in a uniform magnetic field; at t = 0 s, the field begins increasing at a rate of 59 T/s:...
please answer all parts a,b,c,d (17%) Problem 2: A wire, bent into a rectangle with sides a = 0.075 m and b = 0,045 m, is in a magnetic field B directed perpendicularly to the face of the wire, as shown. The perpendicular component is a function of time as B(t) = Asinot), where A = 0.45 T. 6 = 9 rad/s. In this problem, take the normal vector to the surface of the loop to be parallel to the...
ANSWER ALL PLEASE Question 35 2 pts A charged particle (with q = 1.0 x 10-2 C) that is moving through a uniform magnetic field has a velocity v = (6.0 x 105m/s) i + (4.0 x 105m/s) k when it experiences a force F due to the magnetic field. If B = (-3.0 x 10-3T)i + (4.0 x 10-3T)j + (5.0 x 10-3T)k, calculate the force, in N (in terms of unit vectors). Equation: F=qvxB OF=-(3.0 N)i - (6.0N)j...
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