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QUESTION 33 A simply supported steel beam with two eccentric loads as shown in the figure...
QUESTION 33 The simply supported beam shown in the figure (18) below is subjected to a...
QUESTION 33 The simply supported beam shown in the figure (18) below is subjected to a 3 kN/m uniformally distributed load. The beam has modulus of elasticity of E-200 GPa) and area moment of inertia equals to (/ 12.5 x 10 mm).Answer [Question 33-Question 361 3 kN/m 4 m Figure (18) The support reaction at point A in the y-direction (RAJ: (CLO6) (1 Point) 6.3 kN 48 kN 2 kN 6 kN
8 O -01722 mm O -0.1388 mm QUESTION 37 For the 2014-T6 aluminum shaft, as shown in figure (18) below. If the shaft having a diameter of 100 mm and the second moment of area of the is (, 10-6 m.)...
8 O -01722 mm O -0.1388 mm QUESTION 37 For the 2014-T6 aluminum shaft, as shown in figure (18) below. If the shaft having a diameter of 100 mm and the second moment of area of the is (, 10-6 m.). And the modulus of elasticity (E-73.1 GPa) Answer [Question 37. 4.908 Question 40 0.5 0.5 m 8 kN 8 kN Figure (18) The support reaction at point A in the y-direction (RAy): (CLO6) (a Point) 2 KN QUESTION 38...
Question 3 For the simply supported steel beam with cross section and loading shown (see Figure...
Question 3 For the simply supported steel beam with cross section and loading shown (see Figure 3a), knowing that uniformly distributed load w=60 kN/m, Young modulus E = 200 GPa, and yield stress Cyield=200 MPa (in both tension and compression). ул 15 mm w=60 kN/m ... 1 B A 15 mm + 300 mm IC - i 2.5m 1 1 15 mm 7.5m 1 150 mm Figure 3a (a) Check if: the beam is safe with respect to yielding (using...
A flanged beam simply supported at both ends as shown in the figure below. Determine the...
A flanged beam simply supported at both ends as shown in the figure below. Determine the steel reinforcements and links required for the beam subject to bending moment and shear forces ood Swt Center-to-center distance btw supports Section Elevation Design parameters: Beam overall depth, h = 750 mm Beam breadth, b = 300 mm c/c distance btw supports = 10050 mm Width of LHS support, Sw1 400 mm Width of RHS support, Sw2 850 mm Slab thickness, h c/c distance...
A 5-m-long simply supported timber beam carries two concentrated loads as shown dimensions of the beam...
A 5-m-long simply supported timber beam carries two concentrated loads as shown dimensions of the beam are shown a) At section a-a e the magnitude of the shear stress in the beam at point H. -7748 KNIm in the beam at point K the beam, at any location within the 5-m span length. V occurs in the beam at any location within the 5-m span length.)diagr. the magnitude of the shear stress (b) At section a-a, (e) Determine the maximum...
QUESTION 1 [15] For the simply supported beam subjected to the loading shown in the figure,...
QUESTION 1 [15] For the simply supported beam subjected to the loading shown in the figure, a) Derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) b) Report the maximum positive bending moment, the maximum negative bending moment, and their respective locations. 36 KN 180 KN-m X B C D 4 m 5 m 3 m Figure 1
The steel beam ABCD shown in the figure is simply supported at Cand supported at Band...
The steel beam ABCD shown in the figure is simply supported at Cand supported at Band D by shoulder steel bolts, each having a diameter of 10 mm. The lengths of BE and DF are 50 mm and 60 mm, respectively. The beam has a second area moment of 21 x 103 mm4. Prior to loading, the members are stress free. A force of P= 2000 N is then applied at point A. Using procedure 2 of Sec. 4– 10,...
QUESTION 34 The simply supported beam shown in the figure below is subjected to a 3...
QUESTION 34 The simply supported beam shown in the figure below is subjected to a 3 kN concentrated force. The beam has modulus of elasticity of E-70 GPa and area moment of inertia equals to l-126x10-6 m4 Question 34- Question 38] 3 kN 5 According to successive integration method Ely(x) = x3 (x-2)3 6 12 4 () x2 8 (x+ 1)2 4 QUESTION 36 C2 = 0 QUESTION 36 C2 - 0 2 3 QUESTION 37 C1- 1.33 1.5 2.3...
2. A beam is composed of two IPE 100 steel sections as shown in the figure....
2. A beam is composed of two IPE 100 steel sections as shown in the figure. To increase its strength, it is proposed that two steel plates of thickness 8 mm be added at its top and bottom flanges. a) Determine the support reactions. b) Draw shear force and bending moment diagrams. c) If the allowable bending stress of the beam is 300 MPa determine the required width d of the plates to safely support the load. (Use Imar =...
Question 2 Simply supported beam ABC is subject to a point load and the patch loads...
Question 2 Simply supported beam ABC is subject to a point load and the patch loads as indicated in Figure Q2. Assume the beam has a uniform cross-section size. The Modulus of Elasticity E = 210x106 kN/m2, second moment of area l=5x105 m. Determine the deflection of beam ABC at the middle point using MacCaulay's Method. Total (15) marks. -30 KN -6 kN/m -3 kN/m B 3 m 4 m * Figure Q2: Simply supported beam ABC
QUESTION 33 The simply supported beam shown in the figure (18) below is subjected to a 3 kN/m uniformally distributed load. The beam has modulus of elasticity of E-200 GPa) and area moment of inertia equals to (/ 12.5 x 10 mm).Answer [Question 33-Question 361 3 kN/m 4 m Figure (18) The support reaction at point A in the y-direction (RAJ: (CLO6) (1 Point) 6.3 kN 48 kN 2 kN 6 kN
8 O -01722 mm O -0.1388 mm QUESTION 37 For the 2014-T6 aluminum shaft, as shown in figure (18) below. If the shaft having a diameter of 100 mm and the second moment of area of the is (, 10-6 m.). And the modulus of elasticity (E-73.1 GPa) Answer [Question 37. 4.908 Question 40 0.5 0.5 m 8 kN 8 kN Figure (18) The support reaction at point A in the y-direction (RAy): (CLO6) (a Point) 2 KN QUESTION 38...
Question 3 For the simply supported steel beam with cross section and loading shown (see Figure 3a), knowing that uniformly distributed load w=60 kN/m, Young modulus E = 200 GPa, and yield stress Cyield=200 MPa (in both tension and compression). ул 15 mm w=60 kN/m ... 1 B A 15 mm + 300 mm IC - i 2.5m 1 1 15 mm 7.5m 1 150 mm Figure 3a (a) Check if: the beam is safe with respect to yielding (using...
A flanged beam simply supported at both ends as shown in the figure below. Determine the steel reinforcements and links required for the beam subject to bending moment and shear forces ood Swt Center-to-center distance btw supports Section Elevation Design parameters: Beam overall depth, h = 750 mm Beam breadth, b = 300 mm c/c distance btw supports = 10050 mm Width of LHS support, Sw1 400 mm Width of RHS support, Sw2 850 mm Slab thickness, h c/c distance...
A 5-m-long simply supported timber beam carries two concentrated loads as shown dimensions of the beam are shown a) At section a-a e the magnitude of the shear stress in the beam at point H. -7748 KNIm in the beam at point K the beam, at any location within the 5-m span length. V occurs in the beam at any location within the 5-m span length.)diagr. the magnitude of the shear stress (b) At section a-a, (e) Determine the maximum...
QUESTION 1 [15] For the simply supported beam subjected to the loading shown in the figure, a) Derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) b) Report the maximum positive bending moment, the maximum negative bending moment, and their respective locations. 36 KN 180 KN-m X B C D 4 m 5 m 3 m Figure 1
The steel beam ABCD shown in the figure is simply supported at Cand supported at Band D by shoulder steel bolts, each having a diameter of 10 mm. The lengths of BE and DF are 50 mm and 60 mm, respectively. The beam has a second area moment of 21 x 103 mm4. Prior to loading, the members are stress free. A force of P= 2000 N is then applied at point A. Using procedure 2 of Sec. 4– 10,...
QUESTION 34 The simply supported beam shown in the figure below is subjected to a 3 kN concentrated force. The beam has modulus of elasticity of E-70 GPa and area moment of inertia equals to l-126x10-6 m4 Question 34- Question 38] 3 kN 5 According to successive integration method Ely(x) = x3 (x-2)3 6 12 4 () x2 8 (x+ 1)2 4 QUESTION 36 C2 = 0 QUESTION 36 C2 - 0 2 3 QUESTION 37 C1- 1.33 1.5 2.3...
2. A beam is composed of two IPE 100 steel sections as shown in the figure. To increase its strength, it is proposed that two steel plates of thickness 8 mm be added at its top and bottom flanges. a) Determine the support reactions. b) Draw shear force and bending moment diagrams. c) If the allowable bending stress of the beam is 300 MPa determine the required width d of the plates to safely support the load. (Use Imar =...
Question 2 Simply supported beam ABC is subject to a point load and the patch loads as indicated in Figure Q2. Assume the beam has a uniform cross-section size. The Modulus of Elasticity E = 210x106 kN/m2, second moment of area l=5x105 m. Determine the deflection of beam ABC at the middle point using MacCaulay's Method. Total (15) marks. -30 KN -6 kN/m -3 kN/m B 3 m 4 m * Figure Q2: Simply supported beam ABC
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