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One application of Hess's Law (which works for AH, AS, and AG) is calculating the overall...
Using the table of standard entropies and enthalpies of formation, calculate AH°, ASº, and AG° for the following reactions at 298.15 K. (Use only the table of standard entropies and standard enthalpies of formation, not the table of standard Gibbs free energies.) kJ AH; () AS; mol-K mol Compound C(s) 5.7 CO(g) -110.5 197.7 The equation SiO2(s) + 2 Mg(s) Si(s) + 2 CO2(g) -393.5 213.8 MgO(s) C2(g) 223.1 H2(g) 130.7 • AH° kJ HCl(g) 186.9 -92.3 • AS° MK...
(9) A spontaneous process has the change of free energy (a) AG>0 (c) AG = 0 (b) AG <O (d) AH>0 and AS <O (10) A chemical reaction has AH = 10 kJ. AS = 50 J/K at temperature T = 300 K. the reaction AG = J. (a) 5000 (b) -5000 (c) 10000 (d) 50 (11) For reaction: Ag (s) + 2 Cl2 (g) Ag° (aq) +CI (aq), the standard free energy of formation: AGf° (Ag*) = 77.1 kJ/mol,...
(9) A spontaneous process has the change of free energy (a) AG > 0 (b) AG <0 (c) AG = 0 (d) AH >0 and AS <0 (10) A chemical reaction has AH = 10 kJ, AS = 50 J/K at temperature T = 300 K, the reaction AG = (a) 5000 (b)-5000 (c) 10000 (d) 50 (11) For reaction : Ag (s) + 1/2 Cl2 (g) = Agt (aq) + CI+ (aq), the standard free energy of formation: AGE"...
Hess's Law (b) Given the following thermochemical data: 2HNO3(aq) +A920(s) - H2O(1) +2AgNO3(aq) AH = -44.8 kJ Ag20(s) - 2Ag(s) + 1/2O2(9) AH = 31.0 kj H20(1) - H2(9)+1/202(9) AH = 285.8 kJ Use Hess's Law to determine AH for the reaction: Ag(s)+HNO3(aq) → 12H2(9)+AgNO3(aq) AH =
Hess's Law, what is net reaction energy?
Enter all AH values in kJ/mol aHu497kIm AM:-- 756K3mal |M9anstHa00Mg+a 2 O2(8)+H2(e)H2O) AH3 -285.5 kJ/mol AH(MgO) =
Learning Goal: To understand how to use Hess's law to find the enthalpy of an overall reaction. Correct The change in enthalpy, AH, is the heat absorbed or produced during any reaction at constant pressure. Hess's law states that ? H for an overall reaction is the sum of the values for the individual reactions. For example, if we wanted to know the enthalpy change for the reaction PartB What is the enthalpy for reaction 1 reversed? Express your answer...
Potassium chlorate (KCIO3) is often used to generate oxygen according to its decomposition reaction (shown below): A.9 2KCI (s) +302(g) 2KCIO3(s) AH (kJ mol) S (JK mol) KCIO3 (s) KCI (s) 397.8 143.1 -435.9 82.6 O2 (g) 0 205.0 Use the thermochemical data provided above to calculate the standard change in Gibbs Energy (AG for this reaction at a temperature of 298K AH 88.6 kJ (A) 4G. AH-TOs (B) -88.6 kJ (C) -223.4 kJ (D) +223.4 kJ (E) 266.1 kJ...
Ag2S given DeltaH= -32 kj/mol, DeltaG=-40 kj/mol DeltaS= 146 j/k*mol calculate Gibbs free energy for the reaction of dissolving silver sulfide, Ag2S, in water (25 C.) Do the calculations in two ways. Use the standard Enthalpy of formation, deltaH, and entropy S values, and the formula deltaG=deltaH-TdeltaS. Use the standard free energies of formation deltaG and the formula deltaG=deltaG(products)-deltaG(reactants).
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol