After the preparation of a solution with solutions containing Fe3+ and SCN- respectively, the final solution has a concentration of Fe(NCS)2+ 5.0x10-4 M, 1.0x10-3 M Fe3+ and 5.0x10-3 M SCN-. Calculate Kc for the following reaction.
Fe3+ (aq) + SCN- (aq) ↔ Fe(NCS)2+ (aq)
a. |
80 |
|
b. |
100 |
|
c. |
0.01 |
|
d. |
0.001 |
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After the preparation of a solution with solutions containing Fe3+ and SCN- respectively, the final solution...
Consider the following reaction: Fe3+(aq)+SCN−(aq)⇌FeSCN2+(aq) A solution is made containing an initial [Fe3+] of 1.2×10−3 M and an initial [SCN−] of 8.2×10−4 M . At equilibrium, [FeSCN2+]= 1.8×10−4 M . Calculate the value of the equilibrium constant (Kc)(Kc). Express your answer using two significant figures.
1) Consider the following equilibrium: Fe3+(aq) + SCN-(aq) ⇌ FeSCN2+(aq) Initial concentrations: [Fe3+] = 0.590; [SCN-] = 1.239; [FeSCN2+] = 0 The equilibrium concentration of [FeSCN2+]eq = 0.454 M. What is the numerical value of KC for this equilibrium? KC = __________________ 2) Consider the following equilibrium: Fe3+(aq) + SCN-(aq) ⇌ FeSCN2+(aq) Initial concentrations: [Fe3+] = 0.370; [SCN-] = 0.777; [FeSCN2+] = 0 The equilibrium concentration of [FeSCN2+]eq = 0.285 M. What is the equilibrium concentration of Fe3+? [Fe3+]eq =...
-Equilibrium Concentration of [Fe(SCN)2+] – Reacted Concentration of Fe3+ – Reacted Concentration of SCN- – Equilibrium Concentration of Fe3+ – Equilibrium Concentration of SCN- – Equilibrium Constant, Kc M(Fe) M(SCN) 0.00229 0.00206 Test Solutions Concentration Absorbance 1 0 0 2 0.0000618 0.154 3 0.000103 0.22 4 0.000144 0.352 5 0.000206 0.514 From Graph: y = 0.1226x - 0.1198 R² = 0.9844
* PLEASE WRITE OUT ANSWER STEP BY STEP! CONSIDER THE FOLLOWING REACTION: Fe3+(aq)+SCN−(aq)⇌FeSCN2+(aq) A solution is made containing an initial [Fe3+] of 1.2×10−3 M and an initial [SCN−] of 8.2×10−4 M. At equilibrium, [FeSCN2+] = 1.6×10−4 M . PART A: Calculate the value of the equilibrium constant (Kc): [Express your answer using two significant figures] KC = _____________________________
When solutions containing Fe3+(aq) ions and SCN−(aq) ions are mixed together, the following equilibrium is established: Fe3+(aq)+SCN−(aq)⇌FeSCN2+(aq) At equilibrium at some temperature, in 3.0 liters of total solution, there are 0.653 moles of FeSCN2+(aq), 0.0385 moles of Fe3+(aq) and 0.0465 moles of SCN−(aq) . What is K?
Table A. Preparation of Standard solutions of FeSCN2+ 1.0 M HNO3 0.002 M 0.200 M Solution KSCN (mL) Fe(NO3)3 (mL) 0.5 5 [FeSCN2+] (mol/L)* 1 4.0x10^-5 Add 1.0 M 2 1.0 5 8.0x10^-5 HNO3 3 1.5 5 1.2x10^-10 4 2.0 5 1.6x10-4 to each to adjust the volume to 25 mL. 5 2.5 5 2.0x10-4 * Calculate the concentrations of FeSCN2+ in each beaker, assuming that all SCN-ions exist as FeSCN2+. In other words, [FeSCN2+] (in Soln 1) = [SCN-]...
The Common Ion Effect Reaction: Fe3+ + SCN <> Fe(SCN)2+ 1. After the addition of 0.1 M KSCN to test tube 2, what is the color of the solution? How does the addition of KSCN affect the equilibrium of the reaction above? How does this relate to the change, if any, in the color of the solution? Include equations for reactions in your explanation. Color: dark red After the addition of 0.1 M Fe(NO3)3 to test tube 2, what is...
Review |Constants Periodic Table Consider the following reaction: Fe (aq) SCN (aq)FeSCN?+(aq) A solution is made containing an initial | Fe | of 1.2x10-3 M and an initial [SCN of 8.2x104 M At equilibrium, |FeSCN2+-1.8x10-4 M. We were unable to transcribe this image Review |Constants Periodic Table Consider the following reaction: Fe (aq) SCN (aq)FeSCN?+(aq) A solution is made containing an initial | Fe | of 1.2x10-3 M and an initial [SCN of 8.2x104 M At equilibrium, |FeSCN2+-1.8x10-4 M.
Lab Report: Determination of Kc for a Complex Ion Formation tube 2.00e-3 Fe3+ (mL) 2.00E-3M SCN- (mL) water (mL) initial conc. Fe3+ initial conc. SCN- 1 5.00 5.00 0 1.00e-3M 1.00E-3M 2 5.00 4.00 1.00 1.00E-3M 8.00E-3M 3 5.00 3.00 2.00 1.00E-3, 6.00E-3M 4 5.00 2.00 3.00 1.00E-3M 4.00E-3M 5 5.00 1.00 4.00 1.00E-3M 2.00E-3M 10ml of 0.200M Fe3+, 2.00ml of 0.00200M SCN-, AND 8.00ml of water results in an eq. [FeSCN2+] IN Standard Soln.:2.00E-4M Could you please explain how...
Consider the following: A student mixes 5.00 mL 2.00 × 10−3 M Fe(NO3)3 with 3.00 mL 2.00 × 10−3 M KSCN. She finds that in the equilibrium mixture the concentration of FeSCN2+ is 1.28 × 10−4 M. Find Kc for the reaction Fe3+(aq) + SCN−(aq) ↔ FeSCN2+(aq). a. What is the initial concentration of Fe3+ in the reaction mixture? [Fe3+] = ___ x 10-3 M b. What is the initial concentration of SCN- in the reaction mixture? [SCN-] = ___...