The angle θ through which a disk drive turns is given by θ(t)=a+bt−ct3, where a,b and...
The angle θ through which a disk drive turns is given by θ(t)=a+bt−ct3, where a,b and c are constants, t is in seconds, and θ is in radians. When t=0,θ=π/4rad and the angular velocity is 1.70 rad/s , and when 1.30 s , the angular acceleration is 1.30 rad/s2 .
a) What is θ when the angular acceleration is 4.00 rad/s2 ?
b) What is the angular velocity when the angular acceleration is 4.00 rad/s2 ?
Homework Answers
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The angle θ through which a disk drive turns is given
by
θ(t)=a+bt−ct3,
where a,b and...
Exercise 9.7 The angle θ through which a disk drive turns is given by θ(t) =...
Exercise 9.7 The angle \(\theta\) through which a disk drive turns is given by \(\theta(t)=a+b t-c t^{3}\), where \(a, b\) and \(c\) are constants, \(t\) is in seconds, and \(\theta\) is in radians. When \(t=0, \theta=\pi / 4 \mathrm{rad}\) and the angular velocity is \(1.70 \mathrm{rad} / \mathrm{s}\), and when \(1.70 \mathrm{~s}\), the angular acceleration is \(1.35 \mathrm{rad} / \mathrm{s}^{2}\).Part EWhat is θ when the angular acceleration is 2.50 rad/s2?Part FWhat is the angular velocity when the angular acceleration is 2.50 rad/s2?
e and f pls Part E The angle through which a disk drive turns is given...
e and f pls
Part E The angle through which a disk drive turns is given by 0 (t) = a +bt - ct, where a, b, and care constants, t is in seconds, and is in radians. When t=0,0 = */4 rad and the angular velocity is 1.80 rad/s, and when t - 1.60 s, the angular acceleration is 1.40 rad/s For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Calculating angular...
The angle through which a rotating wheel has turned in time t is given by θ...
The angle through which a rotating wheel has turned in time t is given by θ = a t− b t2+ c t4, where θ is in radians and t in seconds. A)Determine an expression for the instantaneous angular velocity ω if t is in seconds. ω = ______ rad/s B)Determine an expression for the instantaneous angular acceleration α if tis in seconds. α = _______ rad/s^2 c)If a = 9.0 rad/s , b = 14.5 rad/s2 , c =...
The angular position of a point on a rotating wheel is given by θ = 3...
The angular position of a point on a rotating wheel is given by θ = 3 + 2t2 + 7t3, where θ is in radians and t is in seconds. (a) At t = 0, what is the point's angular position? rad (b) At t = 0, what is the point's angular velocity? rad/s (c) What is the point's angular velocity at t = 4.0 s? rad/s (d) Calculate the point's angular acceleration at t = 2.0 s. rad/s2 (e)...
The angular position of a point on a rotating wheel is given by θ = 1.6...
The angular position of a point on a rotating wheel is given by
θ = 1.6 + 4.2t2 +
1.7t3, where θ is in radians and
t is in seconds
(a) At t = 0, what is the point's angular position?
(b) At t = 0, what is the point's angular velocity?
(c) What is its angular velocity at t = 4.0 s?
(d) Calculate its angular acceleration at t = 2.0
s.
(e) Is its angular acceleration constant?
is...
A machinist turns on the power to a grinding wheel, which is at rest at t...
A machinist turns on the power to a grinding wheel, which is at rest at t = 0.0 s. The wheel accelerates uniformly for 8.0 s and reaches the operating angular velocity of 80 rad/s. The wheel is then run at that angular velocity for 30 seconds and then the power is shut off. The wheel decelerates uniformly at 5.0 rad/s2 until the wheel stops. Through what total angle has the wheel turned? (a) 2400 radians (b) 3360 radians (c)...
The angular position of a point on the rim of a rotating wheel is given by...
The angular position of a point on the rim of a rotating wheel is given by θ = 6.0t - 2.0t2 + t3, where θ is in radians and t is given in seconds. (a) What is the angular velocity at t = 2 s? rad/s (b)What is the angular velocity at t = 4.0 s? rad/s (c) What is the average angular acceleration for the time interval that begins at t = 2 s and ends at t =...
a b and c please Att -0 a grinding wheel has an angular velocity of 26.0...
a b and c please
Att -0 a grinding wheel has an angular velocity of 26.0 rad/s. It has a constant angular acceleration of 25.0 rad/s until a circuit breaker trips at time t = 1.70 s. From then on, it turns through an angle 438 rad as it coasts to a stop at constant angular acceleration Part A Through what total angle did the wheel turn between t = 0 and the time it stopped? Express your answer in...
Frictional torque causes a disk to decelerate from an angular speed of 3.80 rad/s at t...
Frictional torque causes a disk to decelerate from an angular speed of 3.80 rad/s at t = 0 to 1.40 rad/s at t = 5.10 s. The equation describing the angular speed of the wheel during this time interval is given by dθ dt = ω0e−bt, where b and ω0 are constants. (a) What are the values of b and ω0 during this time interval? b = s−1 ω0 = rad/s (b) What is the magnitude of the angular acceleration...
During a certain time interval, the angular position of a swinging door is described by θ...
During a certain time interval, the angular position of a swinging door is described by θ = 5.01 + 10.9t + 1.98t2, where θ is in radians and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the door at the following times. (a) t = 0 θ = rad ω = rad/s α = rad/s2 (b) t = 3.02 s θ = rad ω = rad/s α = rad/s2
Exercise 9.7 The angle \(\theta\) through which a disk drive turns is given by \(\theta(t)=a+b t-c t^{3}\), where \(a, b\) and \(c\) are constants, \(t\) is in seconds, and \(\theta\) is in radians. When \(t=0, \theta=\pi / 4 \mathrm{rad}\) and the angular velocity is \(1.70 \mathrm{rad} / \mathrm{s}\), and when \(1.70 \mathrm{~s}\), the angular acceleration is \(1.35 \mathrm{rad} / \mathrm{s}^{2}\).Part EWhat is θ when the angular acceleration is 2.50 rad/s2?Part FWhat is the angular velocity when the angular acceleration is 2.50 rad/s2?
e and f pls
Part E The angle through which a disk drive turns is given by 0 (t) = a +bt - ct, where a, b, and care constants, t is in seconds, and is in radians. When t=0,0 = */4 rad and the angular velocity is 1.80 rad/s, and when t - 1.60 s, the angular acceleration is 1.40 rad/s For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Calculating angular...
The angular position of a point on a rotating wheel is given by
θ = 1.6 + 4.2t2 +
1.7t3, where θ is in radians and
t is in seconds
(a) At t = 0, what is the point's angular position?
(b) At t = 0, what is the point's angular velocity?
(c) What is its angular velocity at t = 4.0 s?
(d) Calculate its angular acceleration at t = 2.0
s.
(e) Is its angular acceleration constant?
is...
a b and c please
Att -0 a grinding wheel has an angular velocity of 26.0 rad/s. It has a constant angular acceleration of 25.0 rad/s until a circuit breaker trips at time t = 1.70 s. From then on, it turns through an angle 438 rad as it coasts to a stop at constant angular acceleration Part A Through what total angle did the wheel turn between t = 0 and the time it stopped? Express your answer in...
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