Question

An unknown compound, A, has the formula C6H120. Elucidate the structure of A by scrutinizing its IR, H NMR and DEPT (top) and 3C NMR (bottom) spectra, shown below. Label signals on IR and NMR (show your work) if you want to get all possible points. For NMR labelling refer to Exp 1. 90 ST 2-IMG 80 Transmittance 70 4000 3000 2000 1000 Wavenumbers (cm) بالا 25 24 23 22 21 20 10 18 17 16 15 14 13 12 11 LO OD 08 pre 200 180 160 140 120 100) 80 60 40 20 ppm (multiplet around 80 ppm comes from a solvent. Please disregard it) Compound name Compound structure

label graph please

Answer 1

Compound is Hex-2-One

1720 cm-1 represent carbonyl group

DEPT says , 3 CH2 , 2 CH or CH3 are present

Positive peaks for CH or CH3 and negative peaks for CH2.

1H NMR. . 5 kinds of hydrogens.

Triplet at 0.9 ppm

Quartet at 1.37 and 1.52 ppm

Singlet at 2.1 ppm

Triplet at 2.38 ppm

13 C NMR ...

6 types of carbon atoms, because of 6 Peaks.

Peak at 210 ppm represent ketone group.

IR. Spectra Peak at 1720 Cast = presence of Celbonyle group СЕ О Peaks at 2670,2939, 2962 Capt sp3 Hybridized Sambered HydroCerben (sp) c-h stretching ) - (DEPT) can be Two positive peaks and Three negative peaks 대 3 - CH₂ Present CH & CH3 "H NHR Triplet at oig PPM Quarrer at 1.37 ppry Querket at 1:52 PPM singeet at 2,1 ppmy Triplet at 2.38 PPM Querrel (1.52 ppm] [0.93 PPM 5 kinds of Hydrogens Triplet 1.371 Ruslue) [2.38 PPM] Triplet 2.10 PPM singlet 13C NMR 6 Peaks 6 Type of carbon Peak at 210 PPM Represent | Ketone group 25 PPM 13.8 PPM CH₂ 1210 PPM CH₃ [29. PPM 22 ppm 43 PPM compound Hex-2-one CS canned with CamScanner