Question

A transmission cable is carrying a current I = 22 A in an eaterly direction. A particle of Charge q = 15.0 mu C is moving parallel to the conductor, distance R = 15.0 cm with a velocity V = 55 m/s. The charge experience a force of magnitude: A ray of light is incident on a material with refractive inded n = 2.42. if the material has thickness w = 2.6 mm; How much time does the light take to pass through the material? [Speed of light in air c = 3 Times 10^8 m/s]

Answer 1

8.-

The force is given by:

$F = qv \times B$

Where q is charge, v is speed and B is magnetic field. Also, the magnetic field produced by the wire is:

$B = \frac{\mu _{0}i}{2\pi r}$

Where i is current, miu is permeability of free space and r is distance. So, we first calculate the magnetic field:

$B = \frac{(4\pi x10^{-7}Tm/A)(22A)}{2\pi (0.15m)}$

Now we can calculate the force:

ANSWER is A.

9.-

Using Snell's Law:

$n = \frac{c}{v}$

$v = \frac{c}{n}$

$v = \frac{3x10^{8}m/s}{2.42}$

Now, with the classic movement equation:

$v = \frac{x}{t}$

$t = \frac{x}{v}$

$t = \frac{0.0026m}{1.24x10^{8}m/s}$

ANSWER

I hope it helps!!