Question

An ordinal date consists of a year and a day within it, both of which are integers. The year can be any year in the Gregorian calendar while the day within the year ranges from one, which represents January 1, through to 365 (or 366 if the year is a leap year) which represents December 31.

Ordinal dates are convenient when computing differences between dates that are a specific number of days (rather than months). For example, ordinal dates can be used to easily determine whether a customer is within a 90 day return period, the sell-by date for a food-product based on its production date, and the due date for a baby.

Write a function named ordinalDate that takes three integers as parameters. These parameters will be a day, month and year respectively. The function should return the day within the year for that date as its only result.

Outside of your functions, write code to read a day, month and year from the user and displays the day within the year for that date. You should not use any other class material beyond what we covered to date.

Problem 3: Gregorian Date to Ordinal Date An ordinal date consists of a year and a day within it, both of which are integers. The year can be any year in the Gregorian calendar while the day within the year ranges from one, which represents January 1, through to 365 (or 366 if the year is a leap year) which represents December 31. Ordinal dates are convenient when computing differences between dates that are a specific number of days (rather than months). For example, ordinal dates can be used to easily determine whether a customer is within a 90 day return period, the sell-by date for a food-product based on its production date, and the due date for a baby. Write a function named ordinaldate that takes three integers as parameters. These parameters will be a day, month and year respectively. The function should return the day within the year for that date as its only result. Outside of your functions, write code to read a day, month and year from the user and displays the day within the year for that date. You should not use any other class material beyond what we covered to date. # Sample Run 1 Enter day (-1 to quit): 15 Enter month: 2 Enter year: 2020 46 # Sample Run 2 Enter day (-1 to quit): 16 Enter month: 13 Enter year: 2020 Invalid month entered! Enter day (-1 to quit): # Sample Run 3 Enter day (-1 to quit): 32 Ent 3 Enter year: 2020 Invalid day entered! Enter day (-1 to quit): Some hints: • Write a function to determine whether you have a leap year. This will help to calculate the number of days in February. Here are the criteria for determining a leap year: • Any year that is divisible by 400 is a leap year. • Of the remaining years, any year that is divisible by 100 is not a leap year. • Of the remaining years, any year that is divisible by 4 is a leap year. • All other years are not leap years. . Be sure to check for invalid month and days.

Answer 1

The java code is as follows:-

import java.util.*;
public class Main
{
   static int days []={31,28,31,30,31,30,31,31,30,31,30,31};
   static int ordinalDate(int d, int m, int y)
   {
       if(m>2 && y%4==0 && (y%100!=0 || y%400==0))
           ++d;
       while(--m>0)
           d=d+days[m-1];
       return d;
   }
   public static void main (String[] args)
   {
   Scanner sc=new Scanner(System.in);
   int day=0,month,year,invalid=0;
   int days []={31,28,31,30,31,30,31,31,30,31,30,31};
   while(day!=-1)
   {
       System.out.print("Enter day(-1 to exit): ");
       day=sc.nextInt();
       if(day==-1)
       break;
       System.out.print("Enter month: ");
       month=sc.nextInt();
       System.out.print("Enter year: ");
       year=sc.nextInt();
       if(month>12) //invalid month
       {
       System.out.println("Invalid month entered!\n");
       invalid=1;
       }
       if((year%4==0 && day>29)||(year%4!=0 && day>days[month-1])) //invalid day
       {
       System.out.println("Invalid day entered!\n");
       invalid=1;
       }
       if(invalid==0) //if date is valid
       System.out.println(ordinalDate(day,month,year)+"\n");
       invalid=0;
   }
   }
}

The output of the above code is as follows:-

Enter day(-1 to exit): 15
Enter month: 2
Enter year: 2020
46

Enter day(-1 to exit): 16
Enter month: 13
Enter year: 2020
Invalid month entered!

Enter day(-1 to exit): 32
Enter month: 3
Enter year: 2020
Invalid day entered!

Enter day(-1 to exit): -1

The screenshot of the above code is as follows:-

C Chegg Х - Online Java Compiler - online edi x + onlinegdb.com/online_java_compiler Run Debug Stop Share Save {} Beautify Language Java OnlineGDB beta Main.java online compiler and debugger for clc++ code. compile. run. debug. share. IDE My Projects Classroom new Learn Programming Programming Questions Sign Up Login fy + 4.8K 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 static int days []={31,28,31,30,31,30,31,31,30,31,30,31}; static int ordinalDate(int d, int n, int y) { if(m>2 && y%4==0 && (y%100! =0 || y%400==0)) ++d; while(--m>0) d=d+days[m-1]; return d; } public static void main(String[] args) { Scanner sc=new Scanner(System.in); int day=0,month, year, invalid=0; int days []={31,28,31,30,31,30,31,31,30,31,30,31}; while(day! =-1) { System.out.print("Enter day(-1 to exit): "); day=sc.nextInt(); if(day==-1) break; System.out.print("Enter month: "); month=sc.nextInt(); System.out.print("Enter year: "); year=sc.nextInt(); if(month>12) //invalid month { System.out.println("Invalid month entered!\n"); invalid=1; } if((year%4==0 && day>29)||(year%4!=0 && day>days[month-1])) //invalid day { System.out.println("Invalid day entered!\n"); invalid=1; } if(invalid==0) //if date is valid System.out.println(ordinaldate (day, month, year)+"\n"); invalid=0; Activate Windows Go to Settings to activate Windows. About • FAQ • Blog Terms of Use . Contact Us .GDB Tutorial - Credits . Privacy © 2016 - 2020 GDB Online o IT g AO » ENG 9:13 AM 29/10/2020 20