Question

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:

1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400

Some example leap years are 1600, 1712, and 2016.

Write a program that takes in a year and determines whether that year is a leap year.

Ex: If the input is:

1712

the output is:

1712 is a leap year. 

Ex: If the input is:

1913

the output is:

1913 is not a leap year.

Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.
bool IsLeapYear(int userYear)

Note: This is a lab from a previous chapter that now requires the use of a function.

Program in C++:

#include <iostream>
using namespace std;

/* Define your function here */

int main() {
/* Type your code here. Your code must call the function. */

return 0;
}

Answer 1

`Hey,

Note: Brother if you have any queries related the answer please do comment. I would be very happy to resolve all your queries.

#include <iostream>

using namespace std;
bool IsLeapYear(int year)
{
// If a year is multiple of 400,
// then it is a leap year
if (year % 400 == 0)
return true;
  
// Else If a year is muliplt of 100,
// then it is not a leap year
if (year % 100 == 0)
return false;
  
// Else If a year is muliplt of 4,
// then it is a leap year
if (year % 4 == 0)
return true;
return false;
}
  
int main()
{

int n;
cin>>n;
if(IsLeapYear(n))
{
cout<<n<<" is a leap year.\n";
}
else
{
  
cout<<n<<" is not a leap year.\n";
}
return 0;
}

Kindly revert for any queries

Thanks.