Question

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:

1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400

Some example leap years are 1600, 1712, and 2016.

Write a program that takes in a year and determines whether that year is a leap year.

Ex: If the input is:

1712

the output is:

1712 is a leap year. 

Ex: If the input is:

1913

the output is:

1913 is not a leap year.

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Answer 1

Java code:

import java.util.*;
  
class Main
{
   static boolean checkLeapinputyear(int inputyear)
   {
       if (inputyear % 400 == 0)
           return true;
       if (inputyear % 100 == 0)
           return false;
       if (inputyear % 4 == 0)
           return true;
       return false;
   }
      
public static void main(String[] args)
   {
   Scanner scnr = new Scanner(System.in);
       int inputyear = scnr.nextInt();
       boolean isLeapYear = checkLeapinputyear(inputyear);
       if(isLeapYear==true)
       System.out.println(""+inputyear+" is a Leap year");
       else
       System.out.println(""+inputyear+" is not a Leap year");
  
   }
}
Execution screenshot:

Main.java import java.util.*; 3 class Main 4- 1 static boolean checkLeapinputyear(int inputyear) if (inputyear % 400 == 0) return true; if (inputyear % 100 == 0) return false; if (inputyear % 4 == 0) return true; return false; public static void main(String[] args) Scanner scnr = new Scanner(System.in); int inputyear = scnr .nextInt() boolean isLeapYear = checkLeapinputyear (inputyear); if(isLeapYear==true) System.out.println(""+inputyear+" is a Leap year"); else System.out.println(""+inputyear+" is not a Leap year"); 26 27 } input 1712 1712 is a Leap year
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