Question

please follow format of example output, do in python

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 - leap year Ex: If the input is: 1913 the output is: 1913 - not a leap year

Answer 1

Code:

year = int(input("Enter the year")) #asking user to enter the year
if (year % 4) == 0: #if year is divisible by 4
if (year % 100) == 0: #check the year is century
if (year % 400) == 0: #if year is century check it is divisible by 400 or not
print(year," - leap year") #if yes it is a leap year
else:
print(year," - not a leap year")
else:
print(year," - leap year") #if year is not a century and divisible by 4 is a leap year
else:
print(year," - not a leap year") #if year is not divisible by 4 then it is not a leap year

Code and Output Screenshots:

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