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Fundamentals of Mechanical Manufacturing Technology: Exercise5 Material-removal Rate The rate (MRR) in turning is the volume of material removed per unit time, with the units of m/min De + D t also can be written as MRR = drv Do: Orignal diameter of workpiece,mm Dr: Final diameter of workpiece, mm Davg: Average diameter of workpiece, mm d: Depth of cut, mm f: Feed, mm/rev 4feed rate ofdf-㈢ )-mm, the distance traveled is l mn, the cutting time is Eq. (2) rN Question: A 150mm-ong, 12.5-mm-diameter 304 stainless steel rod is being reduced in diameter to 12.0 mm by turning on a lathe. The spindle rotates at N:400 rpm, and the tool is traveling at an axial speed of 200mm/min. Calculate the cutting speed, material-removal rate, and cutting time. Solution. The cutting speed is the tangential speed of the workpiece. The maximum cutting speed is at the outer diameter, Do, and is obtained form the equation thus Va From the nlformation given, note that the depth of cut is d 120 0.25mm, and the feed is0.mm/rew.Accordingto tq(1), the materal-removal rateisthen 125-12.0 The actual time to cut, according to Eq-(2), is
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Given outer diometer Jnne dliometer spindlle rotae N 400 pm Speed y> aiven 15307 .96 mnn/min = 4-0 0 from egu ahbn MRR MRR-즈치

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