Question

cription ructions The 20 kg rod AB is pin connected at A. if the rod is released from rest at -10° calculate the angular velocity of the rod at the horizontal position, where the spring is unstretched. The rod is 1.2 m long, and as it rotates the spring BC always remains horizontal because of the roller support at C. You may take the spring constant as k-40 N/S. If needed, you can assume that the unstretched length of the spring is 0.2 m. (But you don't need it!) Datum

Answer 1

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given & = 10' in po MA 20kg LAB = 102m , k = 100 Ho, so & AP unstretched spring length = 0.am unstretched position spring! using energy conservation A = MARX L = 20 x 1 2 2 5 = go 6 legne mgr le sine, = 3 2 1 1 2 3 + 6 x 22 3 2) 20 x 9.81 x 12 in 10° = 1 + 9.6 x w 2 + 2 x 40 x (LAB Wycaso) ² 20. 4 4 2 4.8 why + 90 x (1.2 - 1. gcos 109h 7 AB W = 200 63 rad AD Ang