Question

1.) Suppose you roll two fair six-sided dice. What is the probabilty that I rolled a total of 5?

2.) Suppose you roll two fair six-sided die and I announce that the sun of the two die is 6 or less. What is the probabilty that you rolled a total of 5?

Answer 1

rolled together, When two six sided dice are the possible outcomes are (11), (1, 2), (1,3), (1,4), (1,5), (1,6), (2,1), (2, 2), (2,3), 22,4), (2,5), (2,6), (3,1), (3,2), (3, 3), (3,4), (3,5), (3,6) 14,1), (4,2), (4,3) 14,4), (4,5), (4,6) (5,1), 5,2), (5,3), (5,4), (5,5), (5,6) (6.) 6,2), 6,3), 6,4), 65, 6,6) total no. of possible outcomes is 36 1) Pl total is of 5) 1,2,3), (3,2), (4,1)] 2) erdi let the sum is represented by x, then the required probability is 8 (X=5/x-6). .P X=55x5b) = P(x = 5 0 x36) P(X36) PIX=5) P (X26) {x=6} = PELD (1,2), (1,3), 0,4),052 (21), (2, 2), (2,3 134), (3,1), 13, 2), (3,3), 24,1), .2), (5,1)3 = 16 = 4 - 363