Question

Below is the process flow chart for the production of methanol from CO and H₂

Feed 65.0% H2 32.5% CO 2.5 % CHI Product 100 % CH3OH M REACTOR SEPARATOR F R G 6.1 % CH, 31.3% CO 62.6 % H2

Calculate the overall conversion of CO

                  Single pass conversion of CO if R/F   = 4

Answer 1

solution Pure CH₂OH F M Reacter separator 650 Hz 32.5%20 2.5%CHY R G Recycle 6.1%CMy 31.3% co 62.6% H2 basis of Taking f 100 lmols Reaction Cot 2H2 CHLOH Herse methane (Chy) is act as inent so Inert ((Hu) balonce on.overall system ( Process) - Inext feed in streom F sin) (Famos Inert leaves sheom G resin) 0.025 F 0.061 G =) 0.025 X100 mds G 0.061 >> G 40.983 mols → Now Moles of co Moles of Со in feed = 32.5 moles exit the process in stream G 0.313 x 40.9833 mols 12.8276 mols

Overall Xoven (Moles feed in conversion of co in) - (Moles leaving the Process Process (Moles feed in Process) the x 100 % X overalu = 7 32.5 -12.8276 X100 32.5 | Xoveral a 60.531 % Answer. Goverall convesian. of co : Holes consumed to form CHLOH Moles of abor Produced 32,5- 12.8226 P=19.6724 mols mols s Now co balonce at mixing of f and R R given 믐 4 F R= 400 mols since split same. from same stream stream R & G so these composition remains Со feed sto reater (streom 0.325 F + 0.313 R N . 0.313 XUOO 0.325 x 100 t mols - 157.7 mols Moles of co feed to reactor. 0 Single Pass conversion Moles of co consumes in Reader Moles of co feed to Reactor X . :19.6724 157.7 X 100 . X = 12.47 7. y single pass conversion