We are allowed to do 1 question at a time. Please post again for
other questions.
2)
So,
P = fav outcome/total
here,
favorable outcome = (78 + 636)C2 or 714C2
total = 987C2
P = 714C2/987C2
P = 0.5231
TLP LUg Uut prums Calendar Gradebook 2/CL52 > Assessment melika youssef -bability This assignment is past...
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible) a. Compute the probability that a randomly selected peanut M&M is not brown. b. Compute the probability that a randomly selected peanut M&M is yellow or green. c. Compute the probability that two randomly selected peanut M&M’s are both yellow. d....
According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select five peanut M&M's from an extra-large bag of the candies. (Round all probabilities below to four decimal places; 1.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly two of the five M&M's are yellow. Compute the probability that two or...
According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select four peanut M&M's from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly three of the four M&M's are yellow. P(x = 3) Compute the probability...
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible) a. Compute the probability that a randomly selected peanut M&M is not green. b. Compute the probability that a randomly selected peanut M&M is blue or green. c. Compute the probability that two randomly selected peanut M&M’s are both yellow. d....
2. According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select six peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) a.) Compute the probability that exactly two of the six M&M’s are yellow. b.) Compute the probability...
In a recently purchased pack of peanut M&M's, 9 of the 65 peanut M&M's were brown. If we were to use this sample to create a 95% confidence interval, we would get an interval (0.055 < p < 0.222). The Task - buy a package of M&Ms, the package must be larger than a fun-size (+50 pieces) - determine the claimed population percentage of each color M&M (see below) - record the total number of each color M&M in your...
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select five peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly two of the five M&M’s are yellow. Compute the probability that two...
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select peanut M&M’s from an extra-large bag looking for a blue candy. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that the first blue candy is the eighth M&M selected. Compute the probability that...
Consider: two unopened bags of candy (one Skittles, the other M&M's). The manufacturers state the distribution of coloured candies is: M&M's: 23% blue, 21% orange, 17% green, 13% yellow, 12% red, 14% brown Skittles: colours are reportedly distributed evenly, meaning each colour (red, orange, green, blue, yellow, and purple) has a probability of 1/6. Assume that both of these unopened bags have the same number of candies. If they are opened and mixed, and one candy is randomly selected, what...
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select five peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly two of the five M&M’s are yellow. Compute the probability that two or...