Question

The figure shows a 14-cm-diameter loop in three different magnetic fields. The loop's resistance is 0.26 . In (Figure 1), what are the size and direction of the induced current? Express your answer to two significant figures and include the appropriate units. You may want to review (Pages 849 - 851) I= Value Units Figure < 1 of 3 Submit Request Answer Part B (a) B increasing at 0.50 T/s The loop current direction is cow. There is no induced current The loop current direction is cw. Submit Request Answer Olle 9 Type here to search

the question explains the info that is needed

Answer 1

First of all situations in all three figure are same.

Diameter of loop.d=14 cm=0.14 m

Area of loop.A=$\pi$(d/2)²=$\pi$d²/4

Resistance of loop,R=0.26 ohm

And rate of change of magnetic field ,dB/dt=0.50 T/s

Part A.

Magnitude of Induced current is

I=(A/R)(dB/dt)=($\pi$d²/4R)(dB/dt)=($\pi$$\times$0.14²$\times$0.50)/(4$\times$0.26)=3.0$\times$10^-2 A

Part B.

According to lens law induced electric current flows in a direction such that the current opposes the change that induced it.

So

Direction of current in CW direction.