Question

An iodine-clock kinetics experiment was performed by varying the composition of reactant solutions and measuring the resulting rates of reaction.

1)  How do Trials 2 and 3 in the table differ?

2)  Of the proposed mechanisms, which would be supported by the results in the table?

(If possible please include an explanation/thought process)

An iodine-clock kinetics experiment was performed by varying the composition of reactant solutions and measuring the resultin

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Answer #1

Trials 2 and 3 differ in two respects: 1. Trial 2 has twice as much I- as trial 3. 2.Trial 3 has twice as much S2O82- as trial 2.

MECHANISM DETERMINATION: According to the data given in the table, rate of reaction is halved when concentration of I- is halved (comparing trial 1 and 3). Also, the rate is halved when the concentration of S2O82- is halved (comparing trial 1 and 2). So, the rate is directly proportional to concentration of I- and S2O82- . Hence the rate equation becomes:

R= [I- ][S2O82- ]

Writing rate equations for all the mechanisms proposed and comparing it with the actual rate equation: Rate is always calculated from the slow step. Therefore, the rate equations are:

Mechanism 1: R = [I-]2. Therefore, this is incorrect.

Mechanism 2: R = [I- ] [S2O82-] Therefore, this is correct.

Mechanism 3: R = [S2O8·I]3-[I-]. Therefore, this is incorrect.

Mechanism 4: R = [I- ]2 [S2O82-]. Therefore, this is incorrect.

Answer: Mechanism 2


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