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(0.8 point) Feedback Part 1 FeO(s) +H2(g) Fe(s) H2(I) kJ Part 2 (0.8 poin Feedback Feo(s)+...
Starting with the standard free energies of formation from the following table, calculate the values of...
Starting with the standard free energies of formation from the
following table, calculate the values of ΔG° and E°cell of the
following reactions.
Substance
ΔΔG°f
(kJ/mol)
FeO(s)
-255.2
H2(g)
0
Fe(s)
0
H2O(l)
-237.2
Pb(s)
0
O2(g)
0
H2SO4(aq)
-744.5
PbSO4(s)
-813.0
1) FeO(s) +H2(g) ----Fe(s) +H2O(l)
change in G=18kj
E Cell= v
2) 2Pb(s)+O2(g)+2H2SO4(aq)--------2PbSO4(s)+2H2O(l)
change in G=-611.4
E°cell
= V
Using standard heats of formation calculate AH for 4 FeO (s) + O2 (g) 2 Fe...
Using standard heats of formation calculate AH for 4 FeO (s) + O2 (g) 2 Fe Os (s) AHr of FeO (s) - -272.0 kJ/mol 5 AH'T of Fe2O3 (s) = -825.5 kJ/mol
A chemist measures the energy change AH during the following reaction: 2 Fe,O3(s) — 4 FeO(s)+0...
A chemist measures the energy change AH during the following reaction: 2 Fe,O3(s) — 4 FeO(s)+0 (9) AH= 560. kJ Use the information to answer the following questions. This reaction is... Suppose 73.4 g of Fe, O2 react. endothermic. exothermic. Yes, absorbed. Yes, released. No. Will any heat be released or absorbed? If you said heat will be released or absorbed in the second part of this question, calculate how much heat will be released or absorbed. Round your answer...
Given the standard enthalpy changes for the following two reactions: (1) 2Fe(s) +02(g)»2FeO(s) AHo-544.0 kJ (2)...
Given the standard enthalpy changes for the following two reactions: (1) 2Fe(s) +02(g)»2FeO(s) AHo-544.0 kJ (2) 2Zn(s) + O2(g)--2ZnO(s) Δ11°-496.6 kJ what is the standard enthalpy change for the reaction: (3) FeO(s) + Zn(s)-Fe(s) + ZnO(s) ΔΗΡ ? kJ Given the standard enthalpy changes for the following two reactions (1) 2Ni(s) + O2(g)-一-2Ni0(s) ΔΗ。=-479.4 kJ (2) Ni(s) + C12(g)--NiCl2(s) ΔΗ0--305.3 kJ what is the standard enthalpy change for the reaction: (3) 2NiC12(s) + O2(g--2Ni0(s) + 2Cl2(g) H'-? kJ Given the...
For the reaction Fe(s) + 2HCI(aq)FeCl2(s) + H2(g) ΔΗο--7.4 kJ and ΔS°-107.9 J/K The standard free...
For the reaction Fe(s) + 2HCI(aq)FeCl2(s) + H2(g) ΔΗο--7.4 kJ and ΔS°-107.9 J/K The standard free energy change for the reaction of 2.11 moles of Fe(s) at 278 K, 1 atm would be -37.4kJ This reaction is (reactant, product) -78.9 favored under standard conditions at 278 K Assume that Δ Ho and Δ are independent of temperature. For the reaction N2(g) + O2(g)2 NO(g) Δσ 172.7 kJ and ΔS°-24.9 J/K at 318 K and 1 atm. This reaction is (reactant,...
Consider the four reactions listed below for the next question. 1. FeO(s)+CO(g)<->Fe(s)+Co2(g) K=0.403 2. 2C(s)+O2(g)<->2CO(g) K=1x10at16...
Consider the four reactions listed below for the next question. 1. FeO(s)+CO(g)<->Fe(s)+Co2(g) K=0.403 2. 2C(s)+O2(g)<->2CO(g) K=1x10at16 power 3. 2Cl2(g)+2H2O(l)<->4HCl(aq)+O2(g) K=1.9x10 at-15 power 4. C(s)+2H2(g)<->CH4(g) K=27.5 a.Which reaction has the smallest tendency to occur? 1. Reaction a 2. Reaction b 3. Reaction c 4. Reaction d
2. Consider the following three reactions: 2 Fe (s) +6 HCI (aq)-2 FeCls (aq) +3 H2 (g) AH, Fe:Os (s)+6 HCI (aq)2 Fe...
2. Consider the following three reactions: 2 Fe (s) +6 HCI (aq)-2 FeCls (aq) +3 H2 (g) AH, Fe:Os (s)+6 HCI (aq)2 FeCls (aq) + 3 H2O () AHa 2 H2 (g) +O2 (g)2 H2O () AHc Show how these equations must be summed together according to Hess's Law to determine AH for the combustion of iron (target equation shown below). Also show clearly how the AH values of each of the three reactions must be manipulated to determine the...
The following reaction is endothermic. Cu(OH)2(s) Cu(s) + O2(g) + H2(g) AH(1) = 450 kJ Calculate...
The following reaction is endothermic. Cu(OH)2(s) Cu(s) + O2(g) + H2(g) AH(1) = 450 kJ Calculate the enthalpy change for the reaction of the elements to form one mole of Cu(OH)2(s). Cu(s) + O2(g) + H2(g) Cu(OH)2(s) AH(2) =
Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2:...
Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2: Fe2+(aq)/Fe(s) and Zn2+(aq)/Zn(s) Which of the following is correct for the working cells? Standard reduction potentials, 298 K, Aqueous Solution (pH = 0): Cl2(g) + 2e --> 2C1-(aq); E° = +1.36 V Fe3+(aq) + e --> Fe2+(aq); E° = +0.77 V Cu2+(aq) + 2e --> Cu(s); E° = +0.34 V 2H+(aq) + 2e --> H2(g); E° = 0.00 V Pb2+(aq) + 2e --> Pb(s);...
NO−3(aq)+4H+(aq)+3e−→NO(g)+2H2O(l) E∘=0.96V ClO2(g)+e−→ClO−2(aq) E∘=0.95V Cu2+(aq)+2e−→Cu(s) E∘=0.34V 2H+(aq)+2e−→H2(g) E∘=0.00V Pb2+(aq)+2e−→Pb(s) E∘=−0.13V Fe2+(aq)+2e−→Fe(s) E∘=−0.45V You may want to...
NO−3(aq)+4H+(aq)+3e−→NO(g)+2H2O(l) E∘=0.96V ClO2(g)+e−→ClO−2(aq) E∘=0.95V Cu2+(aq)+2e−→Cu(s) E∘=0.34V 2H+(aq)+2e−→H2(g) E∘=0.00V Pb2+(aq)+2e−→Pb(s) E∘=−0.13V Fe2+(aq)+2e−→Fe(s) E∘=−0.45V You may want to reference (Pages 898 - 902) Section 19.4 while completing this problem. Part A Use data from the table above to calculate E∘cell for the reaction. Fe(s)+2H+(aq)→Fe2+(aq)+H2(g) Express your answer using two decimal places.
Starting with the standard free energies of formation from the
following table, calculate the values of ΔG° and E°cell of the
following reactions.
Substance
ΔΔG°f
(kJ/mol)
FeO(s)
-255.2
H2(g)
0
Fe(s)
0
H2O(l)
-237.2
Pb(s)
0
O2(g)
0
H2SO4(aq)
-744.5
PbSO4(s)
-813.0
1) FeO(s) +H2(g) ----Fe(s) +H2O(l)
change in G=18kj
E Cell= v
2) 2Pb(s)+O2(g)+2H2SO4(aq)--------2PbSO4(s)+2H2O(l)
change in G=-611.4
E°cell
= V
Using standard heats of formation calculate AH for 4 FeO (s) + O2 (g) 2 Fe Os (s) AHr of FeO (s) - -272.0 kJ/mol 5 AH'T of Fe2O3 (s) = -825.5 kJ/mol
A chemist measures the energy change AH during the following reaction: 2 Fe,O3(s) — 4 FeO(s)+0 (9) AH= 560. kJ Use the information to answer the following questions. This reaction is... Suppose 73.4 g of Fe, O2 react. endothermic. exothermic. Yes, absorbed. Yes, released. No. Will any heat be released or absorbed? If you said heat will be released or absorbed in the second part of this question, calculate how much heat will be released or absorbed. Round your answer...
Given the standard enthalpy changes for the following two reactions: (1) 2Fe(s) +02(g)»2FeO(s) AHo-544.0 kJ (2) 2Zn(s) + O2(g)--2ZnO(s) Δ11°-496.6 kJ what is the standard enthalpy change for the reaction: (3) FeO(s) + Zn(s)-Fe(s) + ZnO(s) ΔΗΡ ? kJ Given the standard enthalpy changes for the following two reactions (1) 2Ni(s) + O2(g)-一-2Ni0(s) ΔΗ。=-479.4 kJ (2) Ni(s) + C12(g)--NiCl2(s) ΔΗ0--305.3 kJ what is the standard enthalpy change for the reaction: (3) 2NiC12(s) + O2(g--2Ni0(s) + 2Cl2(g) H'-? kJ Given the...
For the reaction Fe(s) + 2HCI(aq)FeCl2(s) + H2(g) ΔΗο--7.4 kJ and ΔS°-107.9 J/K The standard free energy change for the reaction of 2.11 moles of Fe(s) at 278 K, 1 atm would be -37.4kJ This reaction is (reactant, product) -78.9 favored under standard conditions at 278 K Assume that Δ Ho and Δ are independent of temperature. For the reaction N2(g) + O2(g)2 NO(g) Δσ 172.7 kJ and ΔS°-24.9 J/K at 318 K and 1 atm. This reaction is (reactant,...
2. Consider the following three reactions: 2 Fe (s) +6 HCI (aq)-2 FeCls (aq) +3 H2 (g) AH, Fe:Os (s)+6 HCI (aq)2 FeCls (aq) + 3 H2O () AHa 2 H2 (g) +O2 (g)2 H2O () AHc Show how these equations must be summed together according to Hess's Law to determine AH for the combustion of iron (target equation shown below). Also show clearly how the AH values of each of the three reactions must be manipulated to determine the...
The following reaction is endothermic. Cu(OH)2(s) Cu(s) + O2(g) + H2(g) AH(1) = 450 kJ Calculate the enthalpy change for the reaction of the elements to form one mole of Cu(OH)2(s). Cu(s) + O2(g) + H2(g) Cu(OH)2(s) AH(2) =
Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2: Fe2+(aq)/Fe(s) and Zn2+(aq)/Zn(s) Which of the following is correct for the working cells? Standard reduction potentials, 298 K, Aqueous Solution (pH = 0): Cl2(g) + 2e --> 2C1-(aq); E° = +1.36 V Fe3+(aq) + e --> Fe2+(aq); E° = +0.77 V Cu2+(aq) + 2e --> Cu(s); E° = +0.34 V 2H+(aq) + 2e --> H2(g); E° = 0.00 V Pb2+(aq) + 2e --> Pb(s);...
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