Starting with the standard free energies of formation from the following table, calculate the values of ΔG° and E°cell of the following reactions.
Substance | ΔΔG°f (kJ/mol) |
FeO(s) | -255.2 |
H2(g) | 0 |
Fe(s) | 0 |
H2O(l) | -237.2 |
Pb(s) | 0 |
O2(g) | 0 |
H2SO4(aq) | -744.5 |
PbSO4(s) | -813.0 |
1) FeO(s) +H2(g) ----Fe(s) +H2O(l)
change in G=18kj
E Cell= v
2) 2Pb(s)+O2(g)+2H2SO4(aq)--------2PbSO4(s)+2H2O(l)
change in G=-611.4
E°cell = V
Starting with the standard free energies of formation from the following table, calculate the values of...
(0.8 point) Feedback Part 1 FeO(s) +H2(g) Fe(s) H2(I) kJ Part 2 (0.8 poin Feedback Feo(s)+ H2)Fes)+H2O(1) Eo cell-0.093 08 Question (3 points) e See page 891 Starting with the standard free energies of formation from the following table, calculate the values of Δ๙ and E reactions of the following G°f (kJ/mol) 255.2 Substance FeO(s) H2(g) Fe(s) H200) Pb(s) O2(g) 237.2 744.5 Pb504(s) 813.0 Feedback Part 3 (0.8 point) 2Pb(s)+02(8+2H2SO4(a) 2PbSO4(s)+2H20(0) AG385.3 kJ Part 4 (0.8 poin)Feedback 2Pb(s) +O2 (g)...
Starting from the appropriate free energies of formation (provided below) calculate the values of ∆G° (in kJ) and E°cell (in V) at 298 K for the following reaction, 2 Na(s) + 2 H2O(l) <-----> 2 Na+(aq) + 2 OH-(aq) + H2(g) DfG°(Na(s)) = 0.00 kJ mol-1 DfG°(H2O(l)) = -237.13 kJ mol-1 DfG°(Na+(aq)) = -261.91 kJ mol-1 DfG°(OH-(aq)) = -157.24 kJ mol-1 DfG°(H2(g)) = 0.00 kJ mol-1
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