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Starting from the appropriate free energies of formation (provided below) calculate the values of ∆G° (in...

Starting from the appropriate free energies of formation (provided below) calculate the values of ∆G° (in kJ) and E°cell (in V) at 298 K for the following reaction, 2 Na(s) + 2 H2O(l) <-----> 2 Na+(aq) + 2 OH-(aq) + H2(g) DfG°(Na(s)) = 0.00 kJ mol-1 DfG°(H2O(l)) = -237.13 kJ mol-1 DfG°(Na+(aq)) = -261.91 kJ mol-1 DfG°(OH-(aq)) = -157.24 kJ mol-1 DfG°(H2(g)) = 0.00 kJ mol-1

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Answer #1

Na (3) + 2H₂O(l) 2 Nat (aq) + 204 Car + H₂ (9) AG ° = 19, (produch) – 06, (Reactants) = 2 (86; (Nat) + 2 (AG, (obi-)) + AG,

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