Question

Name B. (7 pts) MIPS short answer 1. (3pt) For the following MIPS assembly language program: loop: addi Sto, $to,-1 bne $to, $zero, loop Translate the second instruction into MIPS machine language and write it in hex. 2. (2 pt) Which best describes the reason that we maintain the stack pointer in a register? (circle one) i. The hardware forces use of a stack pointer. ii. We need a local pointer because we are often limited to relative addressing. ili. We need functions to have addresses for use with function pointers in C. iv. The stack pointer is just a legacy concept that no longer serves a purpose (2pt) Write the MIPS assembly language instructions corresponding to the following pseudo-instruction 3. addi $s0, $s1, 0x7FF333

Answer 1

please find the answers below:

Consider first address is 0x00400000 than instructions willl be:

loop(0x00400000) : addi $t0,$t0,-1 = basic instructions==> addi,$8,$0,0xffffffff ===> in hex 0x2108FFFF

(0x00400004) bne $t0,$zero,loop = basic instructions==> bne,$8,$0,0x00400000 ===> in hex 0x15000000

2. As we are limited to addresses in mips we can push values to the stack and later at point can

retrieve data from stack when needed so correct answer is ii,

3. addi $s0,$s1,0x7ff333

it's a three step instructions

a. lui $at,0x0000007f

b. ori $at,$at,0x0000f333

c. add $s0,$s1,$at