Answer with explanation
The reaction is given below
Substitution bromination will occurs more readily at the 1 position than at the 2 position because the intermediate for 1-substitution is more stable than that for 2-substitution. Because resonance forms determine that C-1 has higher reactivity
a) C-1 attack has 2 resonance structures with benzene rings as under
c) C-2 attack has only 1 resonance structure with a benzene ring
Conclusion: 1-substitution is more favorable because the positive charge can be distributed over two positions, leaving one aromatic ring unchanged while only one resonance structure is possible for the 2-substitution intermediate with aromatic ring unchanged. Therfore, position 1 if favourable for bromination
6. Napthalene undergoes electrophilic aromatic substitution. Predict its reactivity (activating or deactivating) and predict where it...
When performing Electrophilic Aromatic Substitution what do we substitute first the activating or deactivating group?
06 Question (1 point) Sort the substituents as activating or deactivating in electrophilic aromatic substitution reactions 1st attempt d See Periodic Table See Hint Substituents (10 images) (Drag and drop into the appropriate area below Cl SO3H
Choose the incorrect statement for the electrophilic aromatic substitution. a) Bromo group deactivating b) Aniline is more reactive than benzene b) Nitrobenzene is meta-directing d) Acetophenone is para-directing e) Biphenyl undergoes electrophilic aromatic substitution.
6. (9 pts) In regards to an electrophilic aromatic substitution reaction, define the 3 compounds shown below as either: a) Activating, ortho, para director b) Deactivating, ortho para director, c) Activating, meta director, d) Deactivating, meta director. CH -ОН -N-CH3 CH3 7. Answer a-c for compounds A-F below dos a. (5 pts) Which compound(s) have an aromatic carbocation intermediate if it underwent an Snl or E1 reaction? b. (5 pts) Which compound(s) would have an anti-aromatic carbocation intermediate if it...
Pyrrole undergoes nitration by electrophilic aromatic substitution. Complete the mechanism by drawing curved arrows, the structure of the charged intermediate, and the structure of the major uncharged product. Omit electron lone pairs and bases. Trole undergoes nitration by electrophilic aromatic substitution. Complete the mechanism by drawing curved arrows, the structure of the charged intermediate, and the structure of the major uncharged product. Omit electron lone pairs and bases.
Arrange the following in order of decreasing reactivity (fastest to slowest) toward electrophilic aromatic substitution: Arrange the following in order of decreasing reactivity (fastest to slowest) toward electrophilic aromatic substitution: COOH бо ob 6
Activating/Deactivating Substituents Below is a list of different substituents and experimental results from attempted electrophilic aromatic substitution. PhNR, PHCN PhCHO PhF PhMe PhoMe PhNH Deactivating Activating PhNO, PhSozH Phl PhH PNHAC POH • Is the aromatic ring an [ electrophile / nucleophile ] in these reactions? Which substituents 'activate the ring (i.e. make it more reactive? 0 Alkyl substituents: Activate OR Deactivate o Halide substituents: Activate OR Deactivate o OH, NH substituents: Activate OR Deactivate o carbonyl groups: Activate OR...
!!! If each compound undergoes electrophilic aromatic substitution, where should the substituent be added? *The choices for each are either ortho/para position OR meta position.* Phenol? Benzaldehyde? Benzoic Acid? Bromobenzene? Nitrobenzene? Toluene?
H 7. Rank the compounds below in order of reactivity to Electrophilic Aromatic Substitution. Rank the most reactive compound as compound 1 and the least reactive compound as compound 5. (5 points) NO2 pada CH SO3H OH 5
-NH2 is one of the most powerful ortho/para activators in electrophilic aromatic substitution. However, attempts to nitrate aniline under standard conditions leads to the formation of m-nitroaniline (3%) with 97% of aniline remaining unchanged. Why is this? Hint: -NH2 is a base as well as an activator. 3. Why are amines more activating than amides? NH2 Aniline is very readily brominated in aqueous conditions at room temperature in comparison to benzene (high temperature and FeBr3 catalysis is required). When aniline...