Question

and guidores, Superheated On this p a vaporare, ma g st the insurated vapor, saturated vode saturated andvaporarea, an brotherm Critical Isotherm Pressure (P) - Specific Volume (v) Diagram Problems involving the Continuity Equation 21. A fluid having a density of 1200 kg/m3 flows in a pipe that has an internal diameter of 60 cm. If 3 m3/sec flows in the pipe, determine the mass flow rate in kilograms per hour. 22. Air flows through a 12 in x 14 in rectangular duct at a rate of 2,000 CFM (cubic feet per minute). Determine the mean flow velocity in the duct.

Answer 1

solution 1 Buty linen that For het water I Thi= 200°F (1826 = 1 But honor Tbm.or. Th= The=100°/ nh=mags flow rate of hot For distillate water Tei= 85°F =T Tee = 150°F = T2 De 0.82 Btu) ibm.R. me = mass flow rate of distillate me - Tume summit me • Heat rejected by hot water heat gainby cold water § or mh 1h (T3-T4) = Me (CP) e. (T2-T1) q, max 1 x 1 200-100) = me.x0.82 x (150-85) 9 mh 2 me 0.82 X 65 100 m 30.533 me Ans, ? This is mass flow vratio

Th= gur solution. "Carnot Engine" source timp (Th) = 1000 °F sink temp. (Tc) = 100°r. and: Produced work (1) = 160,000 ft. lb. 19h-de=w Tea 21 (9) Thermal efficiency 19th). # = - on 0 = 1-0.1 = 0.9 1 = 90%) and 6 Heat supplied low t I 18 anet 19th = OR os, 0.9 = 160,000 gh 160,000 0.9 And oxy Pn= 160 Ph = 177, 777. 78 stulb ©: Heat rejection 102 Wnet - Ph-ge or ce = 9h - What or 0 =177,777.78 -160,000 Pc = 17,777.78 stilb Ans.

Qur. . For abous engine (9). The change in entropy for the heat reception. [PRETE. S:9=fiss} ar 45= Ph 45= 177,777,78 1000 178 ft. lb. of 45= 177.70 ft. lbl of Ans. 6. The entropy change for heat rejection bertions :- ge=Te. As er, as = 2 17,777,78 AS - AS= 177.78 st. lbl of Ans.