5.09 Problem 5.09 A sheet of steel 1.5 mm thick has nitrogen atmospheres on both sides...
Problem 5.09 A sheet of steel 3.6 mm thick has nitrogen atmospheres on both sides at 1200°C and is permitted to achieve a steady-state diffusion condition. The diffusion coefficient for nitrogen in steel at this temperature is 6.9 x 10-11 m2/s, and the diffusion flux is found to be 3.9 x 10 kg/m2-s Also, it is known that the concentration of nitrogen in the steel at the high-pressure surface is 4.7 kg/m3. How far into the sheet from this high...
A sheet of steel 2.2 mm thick has nitrogen atmospheres on both sides at 1200°C and is permitted to achieve a steady-state diffusion condition. The diffusion coefficient for nitrogen in steel at this temperature is 6.8 × 10-11 m2/s, and the diffusion flux is found to be 2.5 × 10-7 kg/m2-s. Also, it is known that the concentration of nitrogen in the steel at the high-pressure surface is 5.1 kg/m3. How far into the sheet from this high-pressure side will...
A sheet of steel 3.8 mm thick has nitrogen atmospheres on both sides at 1200°C and is permitted to achieve a steady-state diffusion condition. The diffusion coefficient for nitrogen in steel at this temperature is 5.1 × 10-11 m2/s, and the diffusion flux is found to be 4.8 × 10-7 kg/m2-s. Also, it is known that the concentration of nitrogen in the steel at the high-pressure surface is 4.7 kg/m3. How far into the sheet from this high-pressure side will...
9. (4 Marks) A sheet of steel 3 mm thick has nitrogen atmospheres on both sides at 900°C and is permitted to achieve a steady-state diffusion condition. The diffusion coefficient for nitrogen in steel at this temperature is 1.85 x 10-10 m2/s, and the diffusion flux is found to be 1.0 x 10-7 kg/m2.s. Also, it is known that the concentration of nitrogen in the steel at the high-pressure surface is 2 kg/m3. How far into the sheet from this...
A sheet of steel 1.7 mm thick has nitrogen atmospheres on both sides at 1200°C and is permitted to achieve a steady-state diffusion condition. The diffusion coefficient for nitrogen in steel at this temperature is 6.8 x 10-11 m/s, and the diffusion flux is found to be 1.4 x 10 kg/m2-s. Also, it is known that the concentration of nitrogen in the steel at the high-pressure surface is 5.5 kg/m. How far into the sheet from this high-pressure side will...
Current Attempt in Progress Support A sheet of steel 3.7 mm thick has nitrogen atmospheres on both sides at 1200 C and is permitted to achieve a steady-state diffusion condition. The diffusion coefficient for nitrogen in steel at this temperature is 6.5x 1011 ms. and the diffusion flux is found to be 34x 10 kg/m2-s. Also, it is known that the concentration of nitrogen in the steel at the high-pressure surface is 5.8 kg/m. How far into the sheet from...
Nitrogen is sometimes diffused into the surface of a steel component in a process called case hardening. Consider a sheet of steel (1.416x10A0) mm thick which has nitrogen atmospheres on both sides at a temperature of 1200°C. The system is permitted to achieve a steady-state diffusion condition. The diffusion coefficient for nitrogen in steel at this temperature is (6.735x10A-11) m2/s. The diffusion flux is found to be (2.52x10A-7) kg/m2-s. It is also known that the concentration of nitrogen at the...
A differential nitrogen pressure exists across a 2-mm-thick steel furnace wall. After some time, steady-state diffusion of the nitrogen is established across the wall. Given that the nitrogen concentration on the high-pressure surface of the wall is 5 kg/m3kg/m3 and on the low-pressure surface is 0.3 kg/m3 , calculate the flow of nitrogen through the wall (in kg/m2.h) if the diffusion coefficient for nitrogen in this steel is 1.0 ×10−10m2/s at the furnace operating temperature. Express your answer to three...
Please show work for problems 1-4 1. Calculate the activation energy for vacancy formation in aluminum, given that the equilibrium number of vacancies at 500°C (773 K) is 7.57 x10m3. The atomic weight and density (at 500°c) for aluminum are 26.98 g/mol and 2.62 g/cm, respectively 2. What point defects are possible for Al,0, as an impurity in Mgo? How many Al ions must be added to form each of these defects? 3. A sheet of steel 4.5 mm thick...
The purification of hydrogen gas is possible by diffusion through a thin palladium sheet. Calculate the number of kilograms of hydrogen that pass per hour through a 1.6-mm-thick sheet of palladium having an area of 0.45 m2 at 500°C. Assume a diffusion coefficient of 1.9 × 10-8 m2/s, that the concentrations at the high- and low-pressure sides of the plates are 4.3 and 0.60 kg/m3 of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.