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What is the theoretical yield in grams of the precipitate when 50.0mL of a 0.200M solution...

What is the theoretical yield in grams of the precipitate when 50.0mL of a 0.200M solution of barium nitrate reacts with 50.0mL of a 0.200M sodium sulfate solution?

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Answer #1

Basoy (s) + 2Na Nog lag) Ba (NO3)₂ (ay)+ Na, soulay) mols of Ba(NO3)₂ = Conex volume - 0.200Mx 0.05 L - 1.08 103 mol moly of

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