Question

A light string can support a stationary hanging load of 24.4 kg before breaking. An object...

A light string can support a stationary hanging load of 24.4 kg before breaking. An object of mass m = 2.93 kg attached to the string rotates on a frictionless, horizontal table in a circle of radius r = 0.819 m, and the other end of the string is held fixed as in the figure below. What range of speeds can the object have before the string breaks?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

The maximum tension for the string is:
T = m g
T = (24.4 kg) (9.81 m/s²)
T = 239.36 N

The tension in a string when the mass is moving in circular motion is given by:
T = m v² / r
so
(239.364 N) = (2.93 kg) v² / (0.819 m)
v = 8.179m/s

Answer:
(0 m/s) ≤ v ≤ (8.179 m/s)

Add a comment
Know the answer?
Add Answer to:
A light string can support a stationary hanging load of 24.4 kg before breaking. An object...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A light string can support a stationary hanging load of 24.4 kg before breaking. An object...

    A light string can support a stationary hanging load of 24.4 kg before breaking. An object of mass m = 3.19 kg attached to the string rotates on a frictionless, horizontal table in a circle of radius r = 0.777 m, and the other end of the string is held fixed as in the figure below. What range of speeds can the object have before the string breaks OSVS m/s m

  • A light string can support a stationary hanging load of 25.4 kg before breaking. An object...

    A light string can support a stationary hanging load of 25.4 kg before breaking. An object of mass m = 3.23 kg attached to the string rotates on a frictionless, horizontal table in a circle of radius r = 0.795 m, and the other end of the string is held fixed as in the figure below. What range of speeds can the object have before the string breaks? OSVS Your response differs from the correct answer by more than 10%....

  • A light string can support a stationary hanging mass of 40 kg before breaking. Determine the...

    A light string can support a stationary hanging mass of 40 kg before breaking. Determine the maximum speed of a 5 kg object tied to one end of the string, while rotating in a circle of radius 0.8 m, on a horizontal frictionless table while the other end of the string is held fixed.

  • a light string can support a stationary hanging mass of 40kg before breaking. determine the maximum...

    a light string can support a stationary hanging mass of 40kg before breaking. determine the maximum speed of a 5kg object tied to one end of a string, while rotating in a circle of radius 0.8m , on a horizontal friction less table while the other end of the string is held fixed.

  • The block shown is pulled a distance d = 1.5 m across a frictionless horizontal surface...

    The block shown is pulled a distance d = 1.5 m across a frictionless horizontal surface at a constant speed by the force shown. If M = 5.0 kg, F = 30 N and = 40°, find: (a) the work done by the force (b) the normal force exerted by the surface A light string can support a stationary hanging mass of 40 kg before breaking. Determine the maximum speed of a 5 kg object tied to one end of...

  • find the maximum speed the stone can attain without breaking the string A stone with a...

    find the maximum speed the stone can attain without breaking the string A stone with a mass of 0.700 kg is attached to one end of a string 0.700 m long. The string will break if its tension exceeds 55.0 N. The stone is whirled in a horizontal circle on a frictionless tabletop; the other end of the string remains fixed. A Review A stone with a mass of 0.700 kg is attached to one end of a string 0.700...

  • Find the acceleration of the hanging mass if the string does not slip on the sphere or the disk

    As shown in the figure below, a uniform solid sphere rotates about a vertical support on a frictionless bearing. A light cord passes around the equator of the sphere, over a uniform solid disk, and is attached to a hanging mass. The sphere, disk and hanging mass all have equal mass M. The sphere and disk have the same radius R.Find the acceleration of the hanging mass if the string does not slip on the sphere or the disk. Express...

  • A small 0.270-kg object moves on a frictionless horizontal table in a circular path of radius...

    A small 0.270-kg object moves on a frictionless horizontal table in a circular path of radius 1.70 m. The angular speed is 9.60 rad/s. The object is attached to a string of negligible mass that passes through a small hole in the table at the center of the circle. Someone under the table begins to pull the string downward to make the circle smaller. If the string will tolerate a tension of no more than 102 N, what is the...

  • A small 0.501-kg object moves on a frictionless horizontal table in a circular path of radius...

    A small 0.501-kg object moves on a frictionless horizontal table in a circular path of radius 1.16 m. The angular speed is 5.51 rad/s. The object is attached to a string of negligible mass that passes through a small hole in the table at the center of the circle. Someone under the table begins to pull the string downward to make the circle smaller. If the string will tolerate a tension of no more than 112 N, what is the...

  • A stone with a mass of 0.700 kg is attached to one end of a string...

    A stone with a mass of 0.700 kg is attached to one end of a string 0.800 m long. The string will break if its tension exceeds 50.0 N. The stone is whirled in a horizontal circle on a frictionless tabletop; the other end of the string remains fixed. A. Find the maximum speed the stone can attain without breaking the string.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT