Solution :
This is the two tailed test .
The null and alternative hypothesis is ,
H0 :
= 5
Ha :
< 5
= 4.962
= 5
= 0.1
n = 16
Test statistic = z
= ( -
) /
/
n
= (4.962 - 5) / 0.1 / 16
= -1.52
Test statistic = -1.52
This is the right tailed test .
P(z <-1.52) = 0.0643
P-value = 0.0643
= 5% = 0.05
P-value >
. Fail to reject the null hypothesis .
B)
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B??
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The
health of employees is monitored by periodically weighing them in.
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PICTURE
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