Question

Question 23 6V switch open Figure 6 What is the potential difference in volts across RD in Fig. 6?

Answer 1

(23)

6 V 3 , US KVL 2 R+RE So from eqn RTRE フー6 RstRp giRE 6 2ー Re+R

curre enhal ditference (12-13). KD Gp volt A RF

(32) So now if you close the switch then no current will go through R_D and we have to put R_D = 0 in all the equations.So the potential difference across the R_BE will be

$V_{BE}=I_{3}(R_{B}+R_{E})=\frac{6}{(R_{B}+R_{E})}(R_{B}+R_{E})=6volt$

(34)The current will be same as I₃ . So

$I_{BE}=I_{3}=\frac{6}{(R_{B}+R_{E})}Amp$

(36)We have to put R_D = 0 here.

So the current through R_DF will be

$I_{DF}=I_{2}-I_{3}=\frac{6}{R_{F}}Amp$

(38)No current will go through R_D because after closing the switch all the current willgo through the zero resistance line.

(40)So there should not be any potential drop across R_D .