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FBD
The 12-kg rod AB is pinned to the 40-kg disk. If the disk is given an angular velocity wp = 100 rad/s while the rod is held s
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SATU TA = { x12x(2) + 4x40 x(0-3)2 + 40x (2) ? 177-8. Kg.m So, (NA), IA W o 177.8 w2 Now, by (Mb), - (Ha), 180 177.802 W2 = 1le single mit 7 Simi lanly when the rod and disk move as a IA af ma l² + 1 m, rt tm, el

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