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Q 5.4: Assume that sample statistic bases on the normal distribution with the mean of 1.5...
When estimating a population mean by a sample mean, the margin of error does NOT depend...
When estimating a population mean by a sample mean, the margin of error does NOT depend on ______. A) The confidence level B) The sample mean C) The sample size D) The population standard deviation What is the sampling distribution of a statistic? A) The distribution of observations of the statistic for all possible sizes of samples from a population B) The distribution of all possible observations of the statistic for samples of a given size from a population C)...
Question 20 1.5/3 Information about a sample is given. Assume that the sampling distribution is symmetric...
Question 20 1.5/3 Information about a sample is given. Assume that the sampling distribution is symmetric and bell-shaped p-0.27 and the standard error is 0.08 Your answer is correct. (a) Indicate the parameter being estimated. incorrect. (b) Use the information to give a 95% confidence interval. The 95% confidence interval is 0.19 to 0.35
Suppose a random sample of 17 is selected from a normal distribution and the sample mean...
Suppose a random sample of 17 is selected from a normal distribution and the sample mean x-bar = 102.5 and the sample standard deviation Sx = 4.3. Is this a z distribution or a t distribution? A. t distribution with 17 degrees of freedom B. t distribution with 16 degrees of freedom C. z distribution D. Cannot be determined Part b construct a 96% confidence interval for the population mean A. 100.17 to 104.83 B. 100.36 to 104.64 C. 100.00...
The difference between the T distribution and the standard normal (z) distribution decreases as the degrees...
The difference between the T distribution and the standard normal (z) distribution decreases as the degrees of freedom increase. True False When estimating the number of responses to be collected in order to achieve a desired margin of error on a proportion, what value should be used for the population proportion if no estimate is available? Enter your answer as a decimal to 2 decimal places. A population is believed to have a standard deviation of 23.1. An analyst wants...
hi there, having trouble with stats homework In a random sample of 22 people, the mean...
hi there, having trouble with stats homework
In a random sample of 22 people, the mean commute time to work was 31.5 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a t-distribution to construct a 80% confidence interval fo the population mean u. What is the margin of error of u? Interpret the results. The confidence interval for the population mean u is ( 29.4, 33.6) (Round to one decimal place as...
Question 21 1.5/3 Information about a sample is given. Assume that the sampling distribution is symmetric...
Question 21 1.5/3 Information about a sample is given. Assume that the sampling distribution is symmetric and bell-shaped. 59 and the standard error is Correct. (a Indicate the parameter being estimated. Your answer should be an expressioncompo dof symbols=吊く>, μ μι . μ2 p, pi p2-ρ ·Pv 2 Incorrect. (D) Use the information to give a 95% cofdence interval. The 95%confidence interval : 492
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.27. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 2.9 8.4 7.2 4.3 6.8 2.7 7.2 4.8...
A sample of 20 heads of lettuce was selected. Assume that the population distribution of head...
A sample of 20 heads of lettuce was selected. Assume that the population distribution of head weight is normal. The weight of each head of lettuce was then recorded. The mean weight was 2.2 pounds with a standard deviation of 0.1 pounds. The population standard deviation is known to be 0.2 pounds. Construct a 95% confidence interval for the population mean weight of the heads of lettuce. State the confidence interval. Sketch the graph. Calculate the error bound.
w e Using a 1-distribution table or software or a calculator, report the statistic which is...
w e Using a 1-distribution table or software or a calculator, report the statistic which is multiplied by the standard error to form the margin or error forto a. 95% confidence interval for a mean with 15 observations b. 95% confidence interval for a mean with 25 observations c. 90confidence interval for a mean with 25 observations 1 Click the icon to view the distribution tablo a.t= Round to three decimal places as needed)
Let the following sample of 8 observations be drawn from a normal population with unknown mean...
Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation: 24, 22, 14, 26, 28, 16, 20, 21. [You may find it useful to reference the t table.) a. Calculate the sample mean and the sample standard deviation (Round intermediate calculations to at least 4 decimal places. Round "Sample mean" to 3 decimal places and "Sample standard deviation" to 2 decimal places.) Answer is complete but not entirely correct. Sample mean...
Question 20 1.5/3 Information about a sample is given. Assume that the sampling distribution is symmetric and bell-shaped p-0.27 and the standard error is 0.08 Your answer is correct. (a) Indicate the parameter being estimated. incorrect. (b) Use the information to give a 95% confidence interval. The 95% confidence interval is 0.19 to 0.35
hi there, having trouble with stats homework
In a random sample of 22 people, the mean commute time to work was 31.5 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a t-distribution to construct a 80% confidence interval fo the population mean u. What is the margin of error of u? Interpret the results. The confidence interval for the population mean u is ( 29.4, 33.6) (Round to one decimal place as...
Question 21 1.5/3 Information about a sample is given. Assume that the sampling distribution is symmetric and bell-shaped. 59 and the standard error is Correct. (a Indicate the parameter being estimated. Your answer should be an expressioncompo dof symbols=吊く>, μ μι . μ2 p, pi p2-ρ ·Pv 2 Incorrect. (D) Use the information to give a 95% cofdence interval. The 95%confidence interval : 492
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.27. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 2.9 8.4 7.2 4.3 6.8 2.7 7.2 4.8...
w e Using a 1-distribution table or software or a calculator, report the statistic which is multiplied by the standard error to form the margin or error forto a. 95% confidence interval for a mean with 15 observations b. 95% confidence interval for a mean with 25 observations c. 90confidence interval for a mean with 25 observations 1 Click the icon to view the distribution tablo a.t= Round to three decimal places as needed)
Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation: 24, 22, 14, 26, 28, 16, 20, 21. [You may find it useful to reference the t table.) a. Calculate the sample mean and the sample standard deviation (Round intermediate calculations to at least 4 decimal places. Round "Sample mean" to 3 decimal places and "Sample standard deviation" to 2 decimal places.) Answer is complete but not entirely correct. Sample mean...
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