Question

Problem IIA In the circuit shown in Figure IIA-(a), a load element (R ohm) is energized by a current source that varies with time as illustrated. FIGURE IIA + V = BI(t) + 12 Vit) C v(t) 1/2 T Vm a. Deduce the wattage W = (W1 + W1) corresponding to power supplied to the load over the total period of T sec (with W1 in the interval, t = 0 to T/2 and W2 in the interval, t = 1/2 to T). Express the answer as a function of time in terms of the charge transferred to the load by the source in each interval of time (Ans hint: Wi(t) = [(21m/T) qı(t) R, qı = (21m/T)xt? in the interval of time: t= 0 to T/2; W2(t) =?, q2 = ?] b. Calculate the total energy expended in the load over the time period T second. (Ans hint: Integrate W(t) over the time intervals) c. Assuming that Vx represents a current-controlled voltage-source (CCVS), what is its possible use in practice?

Please answer all parts. Thank you

Answer 1

Consider the circuit. (a) + = BI(t) -12.00. Define the current in the interval, O V -- m7 :0 < t < Determine the power dissipated in the resistor, W. W, = 1°()R=(4,PR -(2-4) 9.(t)=24 1,=?G.(+)R Define the current in the interval, Isist. 7(0) = (1-7)=741) sist rent in <t<T. <t<T

Determine the power dissipated in the resistor, W. W.=r(e)R=(4=(1-1))* -(247-(1-1) DR 9:(0)=27=(1-1) w = 2940: (I)R (b) Determine the total energy. Rdt + E=IS W (e)dt - W. (1)dt + [;W()dt ( 22, R + C)4-13) 4 Rd+ 760 442 –21 + ") } - 7 61-)[g-** * TRE). 2.): -=[65-66) 277 +7 It +T | R m R - + 24 l - + - E = 81R.

(C) In a current-controlled-voltage source (CCVS) the voltage of the source depends on the current. V: = B1(t) Here, V is a CCVS which depends on the current I(t) multiplied by a constant ß. A CCVS is used where a variable voltage that changes with the current in an element is required. It is multiplied by a constant to get the desired value. (d) Consider the circuit. (b) + V(t) V(t) R 1/2 T V-V.M Define the voltage V(t). V(t)=0 <t<T The charge q is, q=it FI (0)="0) (-1) 9=2(1-1)