A diverging lens has a focal length of -20 cm. An object is placed 50 cm...

Question

Question

A diverging lens has a focal length of -20 cm. An object is placed 50 cm in front of the lens:

(a) Where is the image located? (in cm)

(b) What is the magnification of the image?

(c) Is the image real or virtual?

(d) Is the image erect or inverted?

Please show me how you reasoned the problem, I'm struggling a lot. Thank you!!

Answer 1

Answer #1

focal length = -20cm. object is placed in front of the uns, so object distance u = -50cm. image distance ve = ? Now using the

Answer 2

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