Question

A ball is kicked at an angle of 35 with the ground. a) What should be the initial velocity of the ball so that it hits a target that is 30 meters away at a height meters? b) What is the time for the ball to reach the target? 18 m 30 m

Answer 1

1.8m x = Vocas (35) 30 = U. cas(35°) + ita 30/V8 Cox135°) 1.8 : - (12) 9.8 (30/. Cas(35))? + vo sin (35°) (30/o carese) 3 m Vocos (35°) - 30 79.8/220 tan 25°)-1.8 Vo = 18.3 m/s b) a= * Voces las) = 2.0 sec. - we have used two formulae's in this problem which are x = U. (as (8) t where x is horizontal distance, vo= mitial velocity @ = angle with ground, t = time to reach at some point and y= 1 gt² + Uo sin(a) it where y= vertical distance 9 9.8 m/s2

we have used two formulae's in this problem which are x = U. (as (B) it where x is horizontal distance, vo= nitial velocity o = angle with ground, t = time to reach at some point -lgt² + Yo sin(B) it and 4= distance where y= g= vertical 9.8 m/s2

we have used two formulae's in this problem which are x = U. (as (B) it where x is horizontal distance, vo= nitial velocity o = angle with ground, t = time to reach at some point -lgt² + Yo sin(B) it and 4= distance where y= g= vertical 9.8 m/s2