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Final Average Gender # Hrs worked/wk Race Attendance 21 18 18 19 35 89 84 20 18 17 20 21 26 32 15 81 70 79 82 40 20

o. We want to estimate the percentage of students next semester who eamed a final average of 90 or above. How students must w

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there are 14 students and only 2 have final average of 90 or above

so, sample proportion p = 2/14

margin of error (E) = 0.03

z value for 95% confidence level is 1.96 (using z table)

sample size n = ((1-p)*p)(z/E)^2

= ((1-(2/14)*(2/14)*(1.96/0.03)^2

= 0.9796*4268.44

= 4181.33

= 4182 (rounded to next integer)

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