Answer
there are 14 students and only 2 have final average of 90 or above
so, sample proportion p = 2/14
margin of error (E) = 0.03
z value for 95% confidence level is 1.96 (using z table)
sample size n = ((1-p)*p)(z/E)^2
= ((1-(2/14)*(2/14)*(1.96/0.03)^2
= 0.9796*4268.44
= 4181.33
= 4182 (rounded to next integer)
Final Average Gender # Hrs worked/wk Race Attendance 21 18 18 19 35 89 84 20...
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