Question

3.

If 2.8 mol of NH₃ and 3.2 mol of O₂ are reacted completely, the number of moles of H₂O produced is ___________.

4,

Use the balanced equation H₂SO₄ + Cu ? SO₂ + H₂O + CuSO₄to answer the following questions.

The theoretical mass of sulfur dioxide produced from two moles of sulfuric acid is __________.

Answer 1

n = 2.8 mol of NH3

n = .2 mol of O2 reac

NH3 + O2 -> NO + H2O

Balance equation!

4NH3+ 5O2 -> 4NO + 6H2O

Now, we need to find the limiting reactants (either O2 or Ammonia will finish first)

2.8 mol of NH3 need (5/4) mol of O2, that is 2.8x(5/4) = 3.5 mol of O2 are going to be needed

As you can se,, we only have 3.2 mol of O2, so the O2 is our limiting reactant

3.2 mol of O2 need (4/5) mol of NH3, that is 3.2x(4/5) = 2.56 mol of NH3 will be reacted

Therefore....

5 mol of O2 react to form 6 mol of H2O

If we react 3.2 mol of O2, then we will form 6/5 mol of H2O

That is: 3.2 mol X (6/5) = 3.84 mol of H2O will be formed

3) 3.84 mol of H2O are formed

Now 4)

H2SO4 + Cu -> SO2 + H2O + CuSO4

When balancing:

Cu(s) + 2H2SO4(l) --> CuSO4(s) + SO2(g) + 2H2O(g)

Now, theoretical mass of SO2... we need first theoretical moles of SO2 when 2 moles of H2SO4 react

If 2 moles of H2SO4 react, we can se that 1 mol of SO2 will be formed

Molecular weigth of 1 mol of SO2 = 64 g/gmol

That is our answer (1 mol is produced) so 64 grams of SO2 are produced