Matlab code:
x=[50:0.1:200];
total_length=[];
for i=x
total_length=[total_length i+2*sqrt(80^2+(210-i).^2)];
%leaving x the other two cables have same length so
2*sqrt(80^2+(210-i).^2
%sqrt(80^2+(210-i).^2) this is hypotenuse which can be calculated
by
%pythagorean theorem
end
min_length=min(total_length);
disp('Minimum total length of cables(in ft.):');
disp(min_length);
index=find(total_length==min_length);
min_x=x(index);
disp('value of x for the length of cables to be minimum is(in
ft.):');
disp(min_x);
Output:
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