Question

6) Remedy a) Find the upper quartile Qs and interpret specific to the problem. {8 pts The following is a sample of 20 November utility bills an dollars from a goal: 52.12,,%, 72, 74, 74, 76, 76, 76, 78, 78, 82, 84, 84, 86, 88, 92, 96, 110.

Answer 1

Solution - bills (in The following is a sample of 20 November ukly dollars) from a neighborhood : 2 Mi 76 76 24 88 92 66 68 110 72 74 74 76 78 82 84 84 86 ② Cal and @3) find and the upper interprete auartile, and Specific to the third quartile problem O median = median is the mean of the tenth and eleventh Value: : median = 76+78 median = 77 first Quartile - Call The median of between the fifth this half is found and sixth value - Q) - 72 + 74 Lai = 73 ( Third от Quartile - (93) - The median of this half is found between the fifteenth and sixteenth value. Q3 = 84+86 93=85

Toterpretation - The quamile deviation ( first quartile, medicin and third quantile) is a measure of absolute dispersion than the range. we take a different sample from a population and calculate their quartiles. Here we have to see that the useful for showing range and spread of data.