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SOLUTION :
v = 15.6 m/s in 1 min (60sec)
Acceleration, a = ∆v / t = (15-6 - 0) / 60 = 0.26 m/s^2
Distance covered during constant acceleration , s1
= average velocity * time
= (15.6 - 0)/2 * 60
= 468 m
Distance covered at constant speed for 10.9 min, s2
= speed * time
= 15.6 * 10.9 * 60
= 10202.40 m
Time of deceleration = 4.1 min (246 sec)
Average speed during deceleration = 15.6 / 2 = 7.8 m/s
Distance covered during deceleration, s3
= average speed * time
= 7.8 * 246
= 1918.80 m
Total distance covered, s
= s1 + s2 + s3
= 468 + 10202.40 + 1918.80
= 12589.20 m
Number of revolutions made by small wheel, N = s / (pi d)
Small wheel turns angle through for this
= N * 2 pi
= s/(pi d) * 2pi
= 2s/d
= 2*12589.20 / (0.12*2)
= 104910 rad. (ANSWER)
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