Question

Equation 1 is derived for thin wires - wires whose diameters are very small compared to...

Equation 1 is derived for thin wires - wires whose diameters are very small compared to their distance apart. However, it is not very accurate for wires whose diameters are comparable to their separation distance (as in this experiment). Why? Use a sketch to explain. Equation 1 is∮B.dL=μoI

0 0
Add a comment Improve this question Transcribed image text
Answer #1

the "integral form" of the original Ampère's circuital law is a line integral of the magnetic field around some closed curve C (arbitrary but must be closed). The curve C in turn bounds both a surface S which the electric current passes through (again arbitrary but not closed—since no three-dimensional volume is enclosed by S), and encloses the current. The mathematical statement of the law is a relation between the total amount of magnetic field around some path (line integral) due to the current which passes through that enclosed path (surface integral). It can be written in a number of forms.

In terms of total current, which includes both free and bound current, the line integral of the magnetic B-field (in tesla, T) around closed curve C is proportional to the total current Ienc passing through a surface S (enclosed by C):

\oint_C \mathbf{B} \cdot \mathrm{d}\boldsymbol{\ell} = \mu_0 \iint_S \mathbf{J} \cdot \mathrm{d}\mathbf{S} = \mu_0I_\mathrm{enc}

So in mathematical terms, the diameter must be small compared to the length so that the line and surface integrals could be applied (to use a line integral one must use an actual line path, if the wire has a certain diameter this no longer applies)

Also with the force law:

The best-known and simplest example of Ampère's force law, which underlies the definition of the ampere, the SI unit of current, states that the force per unit length between two straight parallel conductors is

\frac {F_m} {L} = 2 k_A \frac {I_1 I_2 } {r},

where kA is the magnetic force constant from the Biot–Savart law, Fm/L is the total force on either wire per unit length of the shorter (the longer is approximated as infinitely long relative to the shorter), r is the distance between the two wires, and I1, I2 are the direct currents carried by the wires.

This is a good approximation if one wire is sufficiently longer than the other that it can be approximated as infinitely long, and if the distance between the wires is small compared to their lengths (so that the one infinite-wire approximation holds), but large compared to their diameters (so that they may also be approximated as infinitely thin lines).

Add a comment
Know the answer?
Add Answer to:
Equation 1 is derived for thin wires - wires whose diameters are very small compared to...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Experiment 12 Thin Lenses Purpose The purpose of this experiment is to veily the thin lens equati...

    just the conclusion and the question parts + the graph of M versus q thanks! Experiment 12 Thin Lenses Purpose The purpose of this experiment is to veily the thin lens equation and to determine the focal length of an optical thin lens Apparatus The apparatus used in this experiment consists of an opical bench, a light source with built-in object, a thin lens, a screen and a smaill plastic scale. Theory A thin lens is an optical system with...

  • 019 HW02 pdf+ oads/P122 Spring2019, HW02.pdf Problem 1: Two very thin parallel infinite sheets of insulating...

    019 HW02 pdf+ oads/P122 Spring2019, HW02.pdf Problem 1: Two very thin parallel infinite sheets of insulating material are placed as shown in the figure. The left sheet has a charge placed on it with uniform surface charge density +0o and the right sheet has charge placed on it with uniform surface charge density -Lo- cated between the two objects is a solid perfectly conducting sphere The net charge on the sphere is zero. The radius of the sphere R is...

  • 1. (a) We need to calculate accurate values of the function for very large values of x. However, it is found that ju...

    1. (a) We need to calculate accurate values of the function for very large values of x. However, it is found that just programming this formula into a computer gives very poor accuracy for large x Explain why this happens, and show how to re-write the function so that it can be used reliably, even when x is large. [6 points] (b) In diffraction theory, it is sometimes necessary to evaluate the function sin θ f(x) for small to moderate...

  • 4. The equation mgy for gravitational potential energy is valid only for objects near the surface...

    4. The equation mgy for gravitational potential energy is valid only for objects near the surface of a planet. Consider two very large objects of mass m1 and m2, such as stars or planets, whose centers are separated by the large distance r. These two large objects exert gravitational forces on each other.The gravitational potential energy is U = − Gm1m2 r where G = 6.67 × 10−11Nm2/kg2 is the gravitational constant. (a) Sketch a graph of U versus r....

  • Worksheet for Exploration 27.1: Map Field Lines and Determine Forces in the animation there is an...

    Worksheet for Exploration 27.1: Map Field Lines and Determine Forces in the animation there is an object undemath the gray circle that creates magnetic field # Use the compares to determine the direction of the magnetic field. Sketch the vector fund and the Geld lines for each configuration Configuration 1 sketch Configuration 2 sketch: Check your field ane diagrams by double clicking on the animation to show a field line the Add a wire with current coming out of the...

  • Only A and B please :) The equation mgy for gravitational potential energy is valid only...

    Only A and B please :) The equation mgy for gravitational potential energy is valid only for objects near the surface of a planet. Consider two very large objects of mass m_1 and m_2, such as stars or planets, whose centers are separated by the large distance r. These two large objects exert gravitational forces on each other. The gravitational potential energy is U = -Gm_1 m_2/r where G = 6.67 times 10^-11 Nm^2/kg^2 is the gravitational constant. (a) Sketch...

  • Problem 7 (20 points): Each graph below shows the relative intensity versus 0 for a double slit experiment. The horizontal scale is the same for all graphs. The only possible differences among the ca...

    Problem 7 (20 points): Each graph below shows the relative intensity versus 0 for a double slit experiment. The horizontal scale is the same for all graphs. The only possible differences among the cases are the values of the slit width (a) and distance between the centers of the slits (d). Case For each of the three cases, calculate the ratio- a) 0.5 b) Rank the cases according to distance between the centers Case 2 of the slits (d), from...

  • 2. In lecture, we talked about the heat equation on a thin, laterally insulated rod. There...

    2. In lecture, we talked about the heat equation on a thin, laterally insulated rod. There are many other domains on which you might want to determine the temperature. In this question, we explore the temperature on a wire that has been formed into a circle. thin wire, length 2L, laying flat on [-L,L] bend wire into a circular shape result is a circular wire where the ends x=L and x=-L correspond to one point now. While the PDE remains...

  • Question 5: How would dust and oil on the glass plates affect the results? EXPERIMENT 10 THIN FILM I...

    Question 5: How would dust and oil on the glass plates affect the results? EXPERIMENT 10 THIN FILM INTERFERENCE Light from a monochromatic source is shined downward on two glass plates that are separated at one end by a hair. Light that is reflected from the top and bottom surfaces of the wedge-shaped thin film of air undergoes interference, and a series of dark and light lines are seen. By counting the number of dark or light lines over a...

  • Consider a very (infinitesimally!) thin but massive rod, length L (total mass M), centered around the...

    Consider a very (infinitesimally!) thin but massive rod, length L (total mass M), centered around the origin, sitting along the x-axis. (So the left end is at (-L/2, 0,0) and the right end is at (+L/2,0,0) Assume the mass density λ (which has units of kg/m)is not uniform, but instead varies linearly with distance from the origin, λ(x) = c|x|. a) What is that constant “c” in terms of M and L? What is the direction of the gravitational field...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT