Question

Use the References to access important values if needed for this question. The following thermochemical equation is for the reaction of sulfur dioxide(g) with oxygen(g) to form sulfur trioxide(g) 2502(g) O2(g)-_-2S03(g) H -198 kJ How many grams of SO (g) would have to react to produce 36.3 kJ of energy? grams eq 9 more group attempts remaining Submit Answer Retry Entire Group eq req req

Answer 1

when -198.0 KJ of heat is involved, 2 mol of SO2 is reacting

So,

for -36.5 KJ, mol of SO2 = -36.5*2/-198.0 KJ

= 0.3687 mol

Molar mass of SO2,

MM = 1*MM(S) + 2*MM(O)

= 1*32.07 + 2*16.0

= 64.07 g/mol

use:

mass of SO2,

m = number of mol * molar mass

= 0.3687 mol * 64.07 g/mol

= 23.62 g

Answer: 23.6 g