Question

Note: Respond To All Questions From Part A To C

A. Write Four Conceptual Multiple Choice Questions and Included Your Answer Key For Your Questions for carbohydrates B. Write Four Conceptual Multiple Choice Questions and Included Your Answer Key For Your Questions for monosaccharaides C. Write Four Conceptual Multiple Choice Questions and Included Your Answer Key For Your Questions for cellulose

0 0
Add a comment Improve this question Transcribed image text
Answer #1

A. Multiple choice questions for Carbohydrates:

1. Carbohydrates are defined as:

i. Polyhydroxyaldehydes or ketones or substances which produce them upon hydrolysis

ii. Biopolymers of alpha amino acids linked by peptide bonds

iii. Consists of fatty acids and glycerol

iv. Consists of sugar, phosphate groups

Answer: i. Polyhydroxyaldehydes or ketones or substances which produce them upon hydrolysis

Explanation: Carbohydrates are polyhydroxyaldehydes or ketones or substances which produce them upon hydrolysis

Biopolymers of alpha amino acids linked by peptide bonds are called as proteins

Fats consists of fatty acids and glycerol

Nucleic acids consists of sugar, phosphate groups
Hence the answer is i.

2. Carbohydrates give a positive result for the following test(s):

i. Molisch Test

ii. Fehling's Test

iii. Seliwinoff's Test

iv. All of the above

Answer: iv. All of the above

Molisch test is a general test for carbohydrates where the aqueous extract of the sugar sample, is treated with alpha naphthol in alcohol. Finally concentrated sulphuric acid is added from the sides of the test tube. Formation of violet color shows the presence of carbohydrates

Fehling's test is done to distinguish reducing and non reducing sugars. Fehling's A and B solution are added to the sample sugar solution and heated. Appearance of red color concludes that sugar is a reducing sugar

Seliwinoff's test is used to identify the hexose sugars which are consisting of ketone group for example. fructose. The sugar solution is treated with seliwinoff's reagent and heated. Red color represents the sample contains a ketose sugar. As all of the tests mentioned in the options were tests done for carbohydrates, the correct choice is all of the above

3. The amount of energy obtained from one gram of carbohydrate is

i. 4 calories

ii. 4 kilocalories

iii. 9 calories

iv. 9 kilocalories

Answer: i. 4 calories

Explanation: Carbohydrates and proteins yield 4 calories of energy per gram. While lipids yield 9 calories of energy.

Difference between calorie and kilocalorie. A calorie is defined as the energy required to increase the temperature of 1 gram of water by 1 degree celsius. As calorie is very little in value, kilocalorie is used to express the energy yields where 1 kilocalorie = 1000 calories

4. Examples of non-carbohydrate substance in the given options:

i. Glucose

ii. Sucrose

iii. Starch

iv. Enzyme

Answer: iv. Enzyme

Explanation: Glucose is a monosaccharide, whereas sucrose is a disaccharide consisting of glucose and fructose and Starch is a homopolysaccharide. All of which are classes of carbohydrates. On the other hand, enzymes are biocatalysts which increases the rate of reaction and specific to substrate and temperature.

B. Four conceptual multiple choice questions for monosaccharides:

1. The general formula of monosaccharides is

i. Cn (H2 O)n-2

ii. Cn (H2 O)n-1
iii. Cn (H2 O)n

iv. Cn H2 O

Answer: iii. Cn (H2 O)n

Explanation: Cn (H2 O)n-2 is the general formula of trisaccarides and Cn (H2 O)n-1 is a general formula of disaccharides and Cn H2 O is not the general formula for classes of carbohydrates. Hence the answer is iii

2. Reference monosaccharide to represent all the other structures of carbohydrates is:

i. Glucose

ii. Glyceraldehyde

iii. Dihydroxyacetone

iv. Erythrose

Answer: ii. Glyceraldehyde

Glyceraldehyde is a triose and contains aldehyde group with formula of C3H6O3 and used to represent the structure of other carbohydrates. Glucose is a hexose and comes later to glyceraldehyde in carbon skeleton. Dihydroxyacetone is a ketose sugar having same general formula with that glyceraldehyde. Erythrose is a tetrose with a formula of C4H8O4 and comes next to glyceraldehyde

3. High water solubility of the monosaccharides is attributed to one of the following:

i. Carbonyl group

ii. Carbon skeleton

iii. Polyhydroxy groups

iv. Both i and ii.

Answer: iii. Polyhydroxy groups

Polyhydroxy groups are responsible for water solubility and play a vital role in storage and transport of monosaccharides in living systems. Carbon skeleton and carbonyl group do not account for water solubility

4. The property of monosaccharides:

i. Non reducing sugars

ii. Complexating sugars

iii. Reducing sugars

iv. Basic sugars

Answer: iii. Reducing sugars

Monosaccharides are reducing sugars due to the presence of aldehyde group or ketone group which can convert to aldehyde by tautomerization. So remaining all other properties like basicity, complexation in the given options are false

C. Four conceptual multiple choice questions for Cellulose:

1. The class of cellulose is:

i. Monosaccharide

ii. Disaccharide

iii. Oligosaccharide

iv. Polysaccharide

Answer: d. Polysaccharide

Starch is a homopolysaccharide which will yield only onekind of monomers upon hydrolysis. The other options like monosaccharides include glucose, fructose; disaccharides include lactose, maltose, sucrose; Oligosaccharides include Stachyose, Rhamninose

2. Identification test for Starch is:

i. Iodine Test

ii. Ruthenium red test

iii. Saliwanoff's test

iv. Bial Orcinol's test

Answer: i. Iodine test

Iodine test gives blue color with starch, whereas winered color with glycogen, ruthenium red test is for identification of mucilage, Seliwinof's test is for identification of ketose sugars, fBial orcinol's test is for pentose sugars detection

3. Chemical structure of starch comprises of the following homopolysaccharides:

i. Amylose and Amylopectin

ii. Glucose and Galactose

iii. Glucose and fructose

iv. Two glucose units

Answer: i. Amylose and Amylopectin

Amylose and amylopectin are the two principal components for starch. Amylose consists of glucose with alpha 1-4 glycosidic bonds. whereas amylose is a branched molecule with glucose in alpha 1-4 linkage in linear chain and alpha 1-6 linkage in branching.

Glucose and galactose units are present in lactose, while glucose and fructose units are seen in sucrose and two glucose units are seen in maltose

4. The main storage form of glucose in plants is :

i. Glycogen

ii. Starch

iii. Glucose

iv. Adenosine Triphosphate (ATP)

Answer: ii. Starch

Starch is depot food source for plants, while glycogen is for animals, Glucose is ready form of energy and not storage form. ATP is the energy currency of the cell but not a energy source

Add a comment
Know the answer?
Add Answer to:
Note: Respond To All Questions From Part A To C A. Write Four Conceptual Multiple Choice...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Note: Respond To All Questions From Part A To C A. Write Four Conceptual Multiple Choice...

    Note: Respond To All Questions From Part A To C A. Write Four Conceptual Multiple Choice Questions and Included Your Answer Key For Your Questions for "shlre Choice Questions and Include B. Write Four Conceptual Multiple Choice Questions and Included Your Answer Key For Your uestions for “rough ER related with nucleus and nucleolus" C. Write Four Conceptual Multiple Choice Questions and Included Your Answer Key For Your Questions for "smooth ER related with nucleus and nucleolus"

  • Note: Write 13 Conceptual Multiple Choice Questions and Included Your Answer Key for Two Pictures Below...

    Note: Write 13 Conceptual Multiple Choice Questions and Included Your Answer Key for Two Pictures Below Write 13 Conceptual Multiple Choice Questions and Included Your Answer Kev for Two Pictures Below Non-cyclic electron flow Non-cvclic electron flow Calin cycle uses 3:2 ATP:NADPH CALVIN CYCLE CALVIN B pheophytin NADP 0 complex Splitting of water releases oxygen Splitting of water 6 releases oxygen 2 H' Pc Pc Light Light 0 Light Light Electron fiow provides energy for chemiosmotic synthesis of Electron flow...

  • Note: Respond To All Questions Bolded In Red Color(Be Sure To Include your Answer Key for...

    Note: Respond To All Questions Bolded In Red Color(Be Sure To Include your Answer Key for each of your questions), Sorry for long questions, Could anyone help me please, Thank you. For Part A To C rite 12 Conceptual Multiple Choice Questions 4 multiple choice questions for each part) Including Answer Key of your question A. Invasive species such as growth and affects B. Life tables C. Coevolution, Anagenesis, Cladogenesis ge 1 of 11 190%C words: 38 English United States)...

  • Note: Respond To All Questions Bolded In Red Color(Be Sure To Include your Answer Key for...

    Note: Respond To All Questions Bolded In Red Color(Be Sure To Include your Answer Key for each of your questions), Sorry for long questions, Could anyone help me please, Thank you. For Part A To C: Write 9 Multiple Choice Questions (3 multiple choice questions for each part) Including Answer Key of your questions How a new species forms, ex: geographic isolation, reproductive isolation mechanical, behavioral How to read the invertebrate phylogenetic tree B. Different barriers to reproduction. ex: post-zygotic,...

  • Note: Write 13 Conceptual Multiple Choice Questions and Included Your Answer Key for Two Pictures Below...

    Note: Write 13 Conceptual Multiple Choice Questions and Included Your Answer Key for Two Pictures Below Write 13 Conceptual Multiple Choice Ouestions and Included Your Answer Kev for Two Pictures Below Priming DNA synthesis Elongation of the new DNA strand Primase joins RNA DNA polymerase can only add dNTPs to a pre-existing strand Leading strand synthesis is continuous in the 5'->3' of DNA Leading strand Parental DNA Primase Okazaki fragments direction ONA polymerase adds DNA ONA polymerase DNA primase adds...

  • Respond To All Questions From Part A To C Respond To All Questions From Part A...

    Respond To All Questions From Part A To C Respond To All Questions From Part A To C A. What are the roles of active transport and osmosis in the opening and closing of stomata? B. What factors control the opening and closing of stomata? C. Why are annual rings of a mature woody dicot stem composed of light and dark sub-rings?

  • Note: Respond To All Questions That Are Highlighted From Part A To B A Write a...

    Note: Respond To All Questions That Are Highlighted From Part A To B A Write a short paragraph for observation B. Write a short paragraph for conclusion Volume: 0.2ml. Refractive Index: 1.386, initial temperature of purified hydrocarbon: 20°C, final temperature of purified hydrocarbon: 26°C, empty vial: 6.251g, vial-liquid: 6.392g, boing point 98°C, atmosphere point: 750 torr Unknown: Letter- D. Identity- heptande Density (6392-6.251)g Density- 0.71g ml Corrected boiling point I Corrected boiling point-0.37°C Corrected Refractive Index 0.00045(6°C-20.0°C) Corrected Refractive Indes-...

  • Note: Respond To All Questions That Are Highlighted From Part A To B(Use 3 graphs for...

    Note: Respond To All Questions That Are Highlighted From Part A To B(Use 3 graphs for part B) A. Was your hypothesis correct or not (our hypothesis: The average size of the L. gigantea limpets has changed because humans are impacting their survival of the larger L. gigantea through crushing them, removing them, or changing their habitat) B. What did your data tell you

  • Part A [30 marks] Conceptual Questions (multiple choice and short answer questions) A1-A5 refers to the...

    Part A [30 marks] Conceptual Questions (multiple choice and short answer questions) A1-A5 refers to the velocity vector plots shown bolow for the flow over a cylinder: Flow A Flow B A1. Flow A has a Reynolds number flow of a) Re 1 b) Re 100 c) Re 1000 d) Re 10 drag coefficient than in Flow B A2. Flow A has a) higher b) lower c) the same A3. Flow A has heat transfer than Flow B a) higher...

  • Note: Respond to All Questions That Are Highlighted In Yellow Color from Part A To B....

    Note: Respond to All Questions That Are Highlighted In Yellow Color from Part A To B. Thanks you Shepherd the zygotes from the ideal population around their life cycle with no migration, and to the new gene pool with no mutation. Has the frequency of allele A changed from its starting value of 0.8? Why or why not? Think a bit more about why your first simulation might have produced genotype frequencies among the zygotes that were different from our...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT