The value of the test statistic for a two-tailed one-mean z-test is z 1.52. Determine the...
The value obtained for the test statistic, z, in a one-mean 2-test is given. Whether the test is two tailed, left tailed, or right tailed is also specified. For parts (a) and (b). determine the P-value and decide whether, at the 1% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. a. The test statistic in a two-tailed test is z= -1.42. The P-value is (Round to three cocimal places as...
The test statistic in a two-tailed test is z=0.34 Determine the P-value and decide whether, at the 10% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. LOADING... Click here to view a partial table of areas under the standard normal curve. The P-value is nothing. (Round to four decimal places as needed.) This P-value ▼ sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because it...
What is the p-value of a two-tailed one-mean hypothesis test, with a test statistic of z0=−1.73? (Do not round your answer; compute your answer using a value from the table below.) z−1.8−1.7−1.6−1.5−1.40.000.0360.0450.0550.0670.0810.010.0350.0440.0540.0660.0790.020.0340.0430.0530.0640.0780.030.0340.0420.0520.0630.0760.040.0330.0410.0510.0620.0750.050.0320.0400.0490.0610.0740.060.0310.0390.0480.0590.0720.070.0310.0380.0470.0580.0710.080.0300.0380.0460.0570.0690.090.0290.0370.0460.0560.068
12. (a) A two-tailed test of a one-sample hypothesis of a mean yields a test statistic of z= 1.47. What's the p-value? (b) A one-tailed test of a two-sample hypothesis involving the difference of sample means yields t= 1.85, with 12 degrees of freedom. What is the p-value?
The test statistic in a two-tailed test is z= 2.34. Determine the P-value and decide whether, at the 10% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis 囲Click here to view a partial table of areas under the standard normal curve. The P-value is (Round to four decimal places as needed.) Partial table of areas under the standard normal curve Second decimal place in z z 0.00 0.010.02 0.03 0.04...
You are performing a two-tailed test with test statistic z = − 0.51 , find the p-value to 4 decimal places. p-value:
1. Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to reject Upper H 0 for the given level of significance alpha. Two-tailed test with test statistic z= -1.95 and alpha=0.04 P-value= ? (Round to four decimal places as needed.) Reject H0 or fail to reject? 2. Find the critical value(s) for a left-tailed z-test with alpha=0.01. Include a graph with your answer. The critical value(s) is(are) ___ (Round to two...
Determine the oritical value(s) for a one-mean z-test. Draw a graph that ilustrates your answer Aright-tailed test with α.004. Caten toye豈Page 10.helablestaroasunerthe standar normatoune. The ctcal value(s) is (are)□ (Round to two decimal places as needed. Use a comma to separate answers as needed.)
Use technology to find the P-value for a two-tailed test with nequals11 and test statistic t equals 3.075 . P-valuealmost equals nothing (Round to four decimal places as needed.)
The test statistic in a two dash tailedtwo-tailed test is zequals=1.79 Determine the P-value and decide whether, at the 10% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. LOADING... Click here to view a partial table of areas under the standard normal curve. The P-value is (Round to four decimal places as needed.) This P-value sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because it...