Angle of refraction : Using Snell's law
n1sinø1 = n2sinø2
(1)sin36º = (1.4)sinø2
sinø2 = (1/1.4)sin36º
sinø2 = (1/1.4)*.587
ø2 = sin-1(1/1.4)*.587
ø2 = 24.77º
Angle of reflection : 36º
According to the law of reflection, the angle of incidence is equal to the angle of reflection.
PH 142 Labs Normal Material 1: Refractive index n Incident Ray 0 1Rflected Ray Material 2:...
At an interface between an unknown transparent material and water, a ray of light is incident from the water side at an angle of 30.0 degrees to the normal. The refracted ray makes an angle of 25.0 degrees. A) what is the index of refraction for the unknown material? B) what is the critical angle for total internal reflection for the interface described? C) Make a drawing showing the geometry for rays that would undergo total internal reflection at this...
REFLECTION AND REFRACTION OF LIGHT t incident on a reflecting surface. Add the reflected ray to the figure and Figure label 8.3 shows a ray of light on the angles of incidence and reflection. reflecting surface Figure 8.3 Under what conditions is the angle of refraction greater than the angle of incidence? 2. A light ray is incident on a plane interface between two media. The ray makes an incident angle with the normal of 25.0° in a medium whose...
Light of wavelength 500nm traveling in air is incident along the
normal on Face A of a 60-60-60 glass prism of refractive index
1.52, as shown in the figure.
a) The refracted ray is incident to Face B. Calculate the angle
of incidence of the ray, the angle of refraction of the refracted
ray (if any) and the angle of reflection of the reflected ray. Draw
the rays.
b) The reflected ray at Face B is incident on Face C....
At an interface between an unknown transparent materials and water, a ray of light is incident from the water side at an angle of 45 degree to the normal. The refracted ray makes an angle of 36.8 degree with the normal. A) What is the index of refraction for the unknown materials? B) what is the critical angle for total internal reflection for the interface described? C) make a drawing showing the geometry for rays that would undergo total internal reflection...
A ray of light is incident upon a material with an index of refraction of 1.9 at an angle of 45 degrees. What is the speed of the refracted light ray in this material?
water interface (the surface of the lake), it is partly
reflected back into the air and partly refracted
or transmitted into the water. This explains why on the surface of
a lake sometimes you see the reflection of the surrounding
landscape and other times the underwater vegetation.
These effects on light propagation occur because light travels at
different speeds depending on the medium. The index of refraction
of a material, denoted by n, gives an indication of the speed of...
LAB 8: GEOMETRICAL OPTUS: RAY TRACING PART 1 REFRACTION NORMAL FOR THE OPPOSITE PLANE REFRACTED RAY INSTRUCTIONS * PRINT this sheet. * Using a protractor, measure the angle of incidence is the angle of refraction & for the incident plane * Find the index of refraction of the block na sini Sin * Repeat for the opposite face A NORMAL FOR THE TROCIDENT PLANE INCIDENT RAY LIGHT SOURCE LAG 8: GEOMETRICAL OPIS: RAY TRONG PART I: CONVEX LENSE INSTRUCTIONS Print...
In the figure, a light ray in material 1 with index n - 1.40 is incident at the Brewster angle with material 2 with index n - 1.70. If, is equal the Brewster angle for the interface between materials 2 and 3, what must the index ng equal? 0 113 112 A. 2.25 B. 1.85 C 2.06 D. 1.61 E 1.46 2 Send a message to the instructor <Join another session
Ray traveling in air (n = 1) is incident on a flat surface of refractive index n = 1.52. For what angle of incidence are the refractive and reflected rays perpendicular? A ray traveling in vacuum enters a long fiber of refractive index n = 1.5. Show that the ray undergoes total internal reflection for any angle of incidence.
The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.3° what is the index of refraction of the material? Tries 0/20 A light ray strikes this material (from air) at an angle of 34.7° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees). Tries 0/20 Calculate the angle of the refracted ray (in degrees). Tries 0/20 Assume now...