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A protons speed as it passes point A is 5.00x104 m/s. It follows the trajectory shown in the figure. (Figure 1) Part A You m

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work = change in kinetic energy -9 (VB-VM) - m(Vie-va?) - 1.6X16-19(- 40) = {x1.67X1o-27(ve-- (25x108] [VB= 1x 105 mis . [VB

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