In y direction:
a = -9.8 m/s^2
d = -140 m
vi = 0 m/s
use:
d = vi*t + 0.5*a*t^2
-140 = 0 + 0.5*(-9.8)*t^2
4.9*t^2 = 140
t = 5.345 s
In horizontal direction,
distance moved by package = v*time
= 200 m/s * 5.345 s
= 1070 m
So, it should be dropped 1070 m or 1.07 km ahead
Answer: 1.07 km
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A supply plane needs to drop a package of food to scientists working on a glacier in Greenland. The plane flies 200 m above the glacier at a speed of 130 m/s . How far short of the target should it drop the package?
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